字母与三个或更多字母的组合

Question

我想删除单个字符串并希望保留最小长度为 3 及以上的字符串我尝试使用此 if(result.string >= 3) 访问字符串但它给出数组长度所以我尝试访问字符串，但我不能。所以请任何可以帮助我的人

let stringCombinations = (str) => {
    let strLength = str.length;
    let result = [];
    let currentIndex = 0;
    while (currentIndex < strLength) {
      let char = str.charAt(currentIndex);
      let x;
      let arrTemp = [char];
      for (x in result) {
        arrTemp.push("" + result[x] + char);
    }
      result = result.concat(arrTemp);
      currentIndex++;
    }
    return result;
  };
  console.log(stringCombinations("BLADE"));

This is my ouput
output: (31) ["B", "L", "BL", "A", "BA", "LA", "BLA", "D", "BD", "LD", "BLD", "AD", "BAD", "LAD", "BLAD", "E", "BE", "LE", "BLE", "AE", "BAE", "LAE", "BLAE", "DE", "BDE", "LDE", "BLDE", "ADE", "BADE", "LADE", "BLADE"]


This is what I want
["BLA", "BLD", "BAD", "LAD", "BLAD", "BLE", "BAE", "LAE", "BLAE", "BDE", "LDE", "BLDE", "ADE", "BADE", "LADE", "BLADE"]

Answer 1

您想filter your array using the string length:

["B", "L", "BL", "A", "BA", "LA", "BLA", "D", "BD", "LD", "BLD", "AD", "BAD", "LAD", "BLAD", "E", "BE", "LE", "BLE", "AE", "BAE", "LAE", "BLAE", "DE", "BDE", "LDE", "BLDE", "ADE", "BADE", "LADE", "BLADE"]
  .filter(s => s.length >= 3)
  .forEach(s => console.log(s))

Answer 2

如 @shabs 回答中所述，您可以过滤输出数组以满足您的需要。

但是，这里有一个函数，它只会找到匹配最小长度的组合：

function stringCombinations(str, length) {
    let results;

    if (length == 1)
        results = str.split(""); // Append every character
    else
        results = [];

    for (let i = 0; i < str.length; i++) {
        let startChar = str.charAt(i);

        let remainingStr = str.substring(i + 1);
        let subCombinations = stringCombinations(remainingStr, Math.max(1, length - 1));

        subCombinations.forEach(combination => {
            results.push(startChar + combination);
        })
    }

    return results;
}

对于"ABC", 2作为输入，它会给你["AB", "AC", "ABC", "BC"]

字母与三个或更多字母的组合

combination of letters with three and more letters

javascript

arrays

string

random

word