如何使用正则表达式组拆分键和值

Question

我想提取一些数据以在 JS 中构建对象，但我找不到如何使用正则表达式。

在 regex101 上，下面的正则表达式似乎适合，但它不在我的代码中...

这是数据类型：

"TEST_firstname:john_lastname:doe_age:45"

我想提取键和值（键在 "_" 和 ":" 之间，值在 ":" 和 "_"

之间

我试过这个：(?<key>(?<=\_)(.*?)(?=\:))|(?<value>(?<=\:)(.*?)((?=\_)|$))

有人可以帮我找到合适的正则表达式吗？

Answer 1

使用

/([^_:]+):([^_]+)/g

见regex proof。

解释

--------------------------------------------------------------------------------
  (                        group and capture to :
--------------------------------------------------------------------------------
    [^_:]+                   any character except: '_', ':' (1 or
                             more times (matching the most amount
                             possible))
--------------------------------------------------------------------------------
  )                        end of 
--------------------------------------------------------------------------------
  :                        ':'
--------------------------------------------------------------------------------
  (                        group and capture to :
--------------------------------------------------------------------------------
    [^_]+                    any character except: '_' (1 or more
                             times (matching the most amount
                             possible))
--------------------------------------------------------------------------------
  )                        end of

JavaScript代码:

const regex = /([^_:]+):([^_]+)/g;
const str = `TEST_firstname:john_lastname:doe_age:45`;
while ((m = regex.exec(str)) !== null) {
    console.log(`${m[1]} >>> ${m[2]}`);
}

Answer 2

使用String.prototype.matchAll and Array.prototype.reduce将其缩减为key:value对

的对象

const s = "TEST_firstname:john_lastname:doe_age:45";
const m = s.matchAll(/([^:_]+):([^_]+)/g);
const user = [...m].reduce((ob, [m,k,v]) => (ob[k] = v, ob), {});

console.log(user);

如何使用正则表达式组拆分键和值

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