如何通过按下按钮将输入框 (tkinter) 中输入的文本分配给 python 脚本和 运行 脚本中的变量?

How can I assign the text imputed into an entry box (tkinter) to variable in python script and run the script by pressing a button?

我有一个采用文件路径的 python 脚本和 运行 以下脚本:

    file = 'C:/Users/crist/Downloads/Fraction_Event_Report_Wednesday_June_16_2021_20_27_38.pdf'
    
    lines = []
    with pdfplumber.open(file) as pdf:
        pages = pdf.pages
        for page in pdf.pages:
            text = page.extract_text()
            print(text)

我用 tkinter 创建了一个输入框:

     import tkinter as tk

master = tk.Tk()
tk.Label(master, 
         text="File_path").grid(row=0)

e = tk.Entry(master)


e.grid(row=0, column=1)


tk.Button(master, 
          text='Run Script', 
          command=master.quit).grid(row=3, 
                                    column=0, 
                                    sticky=tk.W, 
                                    pady=4)

tk.mainloop()

我想将用户在输入框中输入的 File_path 分配给脚本中的“文件”,并在按下“运行 脚本时将 运行 分配给脚本“ 按钮。我该怎么做?

生成文件对话框比使用 tkinter.Entry:

更好
# GUI.py
from tkinter.filedialog import askopenfilename
import tkinter as tk

# Create the window and hide it
root = tk.Tk()
root.withdraw()

# Now you are free to popup any dialog that you need
filetypes = (("PDF file", "*.pdf"), ("All files", "*.*"))
filepath = askopenfilename(filetypes=filetypes)

# Now use the filepath
lines = []
with pdfplumber.open(filepath) as pdf:
    ...

# Destroy the window
root.destroy()