如何延迟 C++ 中静态对象（记录器）的销毁？

Question

我得到了一个 class，它将应用程序的记录器保存为 unique_ptr。可以通过静态函数设置记录器。此外，显然可以记录消息。我省略了任何线程同步（互斥锁）以使事情变得更容易。

class LoggerWrapper {
 public:
  static void SetLogger(std::unique_ptr<logger::ILogger> new_logger);

  static void Log(const std::string& message);

 private:
  static std::unique_ptr<logger::ILogger> logger_;
};

void LoggerWrapper::Log(const std::string& message) {
  if (!logger_) {
    // cannot log
  } else {
    logger_->OnLogEvent(message);
  }
}

void LoggerWrapper::SetLogger(std::unique_ptr<logger::ILogger> new_logger) {
  logger_ = std::move(new_logger);
}

我的问题是：unique_ptr 在应用程序中的其他一些 class 之前被破坏。 例如Class Foo 的 DTOR 想要记录一些东西，unique_ptr 可能已经被销毁了（目前就是这种情况）。这会导致 ILogger 实现被破坏，导致无法输出日志。

有没有人知道如何轻松解决这个问题？ 我需要以某种方式“延迟”静态 unique_ptr 的破坏。我也尝试将其更改为 shared_ptr，但这只会导致 SIGABRT 出现“调用纯虚拟方法”错误。

提前致谢！

编辑：创建了一个与我的经验相矛盾的最小工作示例。在这种情况下，静态记录器比 Foo class.

EDIT2：我的应用程序使用 exit。这似乎改变了破坏的顺序。

EDIT3：exit 不会破坏本地对象。

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#include <iostream>
#include <memory>
#include <string>

using namespace std;

class ILogger {
  public:
  ILogger() {
      std::cout << "ILogger CTOR" << std::endl;
  }
  ~ILogger() {
      std::cout << "ILogger DTOR" << std::endl;
  }
  
  virtual void OnLogEvent(const std::string& log_message) {
        std::cout << "OnLogEvent: " << log_message << std::endl;
  }
};

class LoggerWrapper {
 public:
  static void SetLogger(std::unique_ptr<ILogger> new_logger) {
  logger_ = std::move(new_logger);
}

  static void Log(const std::string& message) {
  if (!logger_) {
    // cannot log
  } else {
    logger_->OnLogEvent(message);
  }
};

 private:
  static std::unique_ptr<ILogger> logger_;
};

class Foo {
  public:
   Foo(const std::string& name) : name_{name} {
       LoggerWrapper::Log(name_ + ": CTOR");
   }
   ~Foo() {
       LoggerWrapper::Log(name_ + ": DTOR");
   }
  private:
   std::string name_;
};

// declaring logger_ first causes it to be deleted AFTER foo
std::unique_ptr<ILogger> LoggerWrapper::logger_;
std::unique_ptr<Foo> foo;


int main()
{
    LoggerWrapper::SetLogger(std::make_unique<ILogger>());
    foo = std::make_unique<Foo>("Global FOO");
    
    // local variables do NOT get destroyed when calling exit!
    auto foo_local = Foo("Local FOO");

    exit(1);
}

Answer 1

这很简单。

首先你不使用全局静态对象（你不应该那样使用全局状态）。您使用函数静态对象，因此您可以控制 creation/destruction.

的顺序

所以改变这个：

std::unique_ptr<ILogger> LoggerWrapper::logger_;
std::unique_ptr<Foo> foo;

进入：

 class GlobalLogger
 {
     public:
         ILogger& getLogger() {
             static ILogger  logger;  // if you must use unique_ptr you can do that here
             return logger;           // But much simpler to use a normal object.
         }
  };
  class GlobalFoo
  {
      public:
          Foo& getFoo() {
              // If there is a chance that foo is going to 
              // use global logger in its destructor
              // then it should simply call `GlobalLogger::getLogger()`
              // in the constructor of Foo. You then 
              // guarantee the order of creation and thus destruction.
              // Alternatively, you can call it here in thus
              // function just before the declaration of foo.
              static Foo foo;
              return foo;
          }
  };

  // Where you were using `logger_` use `GlobalLogger::getLogger()`
  // Where you were using `foo`     use `GlobalFoo::getFoo()`

如果我们使用您的原始代码作为起点，我们可以这样做：

#include <iostream>
#include <memory>
#include <string>

// Please don't do this.
// This is the number one worst practice.
// 
using namespace std;

class ILogger {
    public:
        ILogger() {
            std::cout << "ILogger CTOR" << std::endl;
        }
        ~ILogger() {
            std::cout << "ILogger DTOR" << std::endl;
        }

        virtual void OnLogEvent(const std::string& log_message) {
            std::cout << "OnLogEvent: " << log_message << std::endl;
        }
};

class LoggerWrapper
{
    // Here store the logger
    // as a static member of this private function.
    // The the SetLogger() Log() functions get this reference.
    static std::unique_ptr<ILogger>& getLogReference() {
        static std::unique_ptr<ILogger> logger;
        return logger;
    }

    public:
        static void SetLogger(std::unique_ptr<ILogger> new_logger) {
            // Save the new reference.
            getLogReference() = std::move(new_logger);
        }

        // Use the logger if it has been set.
        static void Log(const std::string& message) {
            std::unique_ptr<ILogger>& logger_ = getLogReference();
            if (!logger_) {
                // cannot log
            } else {
                logger_->OnLogEvent(message);
            }
        };
};

class Foo {
    public:
        Foo(const std::string& name) : name_{name} {
            // This calls Log()
            // Which calls getLogReference()
            // Which forces the creation of the function static
            // variable logger so it is created before this
            // object is fully initialized (if it has not already
            // been created).
            // 
            // This means this object was created after the logger
            LoggerWrapper::Log(name_ + ": CTOR");
        }
        ~Foo() {
            // Because the Log() function was called in the
            // constructor we know the loger was fully constructed first
            // thus this object will be destroyed first
            // so the logger object is guaranteed to be
            // available in this objects destructor
            // so it is safe to use.
            LoggerWrapper::Log(name_ + ": DTOR");
        }
    private:
        std::string name_;
};


std::unique_ptr<Foo>& globalFoo() {
    // foo may destroy an object created later
    // that has a destructor that calls LoggerWrapper::Log()
    // So we need to call the Log function here before foo
    // is created.
    LoggerWrapper::Log("Initializing Global foo");
    // Note: Unless somebody else has explicitly called SetLogger()
    // the above line is unlikely to log anything as the logger
    // will be null at this point.

    static std::unique_ptr<Foo> foo;
    return foo;
}

int main()
{
    LoggerWrapper::SetLogger(std::make_unique<ILogger>());
    globalFoo() = std::make_unique<Foo>("Global FOO");

    // local variables do NOT get destroyed when calling exit!
    auto foo_local = Foo("Local FOO");

    exit(1);
}

Answer 2

静态（全局）对象的创建和销毁顺序未定义。这给您留下了几个选择。

不要使用全局对象，只使用原始指针，您可以按正确的顺序销毁自己。
使用指向您永远不会破坏的记录器的指针。这在技术上是内存泄漏，但内核会在您的应用程序退出时进行清理。
为您的记录器使用 shared_ptr。每个使用记录器的对象都会得到一个 shared_ptr，记录器将在最后一个对象被销毁后被清理。

如何延迟 C++ 中静态对象（记录器）的销毁？

How to delay destruction of static object (logger) in C++?

c++

pointers

logging

static

destructor