组合不同的列 powershell

Question

我需要合并这种格式的 csv 条目：

ID, "Name", "Sex",  "Age"
1, "John", "m", "24"
2, "John", "m", "28"
2, "John", "m", "30"
3, "Melissa", "f", "24"
3, "Melissa", "f", "26"

至：

ID, "Name", "Sex", "Age", "Age" ,"Age"
1, "John", "m", "24", "28", "30"
3, "Melissa", "f", "24", "26"

到目前为止我得到了什么：

$csvData = Import-Csv 'test.csv'
$csvData | Group-Object "ID" | ForEach-Object {
    [PsCustomObject]@{
        "ID" = $_.Name
        "Sex" = $_.Group."Sex" -join '","'
        "Age" = $_.Group."Age" -join '","'
    }
} | Export-Csv 'test_output.csv' -NoTypeInformation

哪个 returns 我这个：

"ID","Name", "Sex", "Age"
"1", "John", "John", "John", "m", "m", "m", "24", "28", "30"
"2", "Melissa", "Melissa", , "f", "f", "24", "26"

我该如何解决这个问题？

Answer 1

如果我的理解是正确的，那么这只是 PowerShell foo 的练习，而不是有意义的数据操作。

在此前提下：创建所需输出（并最终得到有效的 csv）的一种方法是为要包含在合并对象中的每个“年龄”值添加编号属性。

$csvData = Import-Csv 'test.csv'
$csvData | Group-Object Name | ForEach-Object {

    $obj = [ordered]@{
        ID = $_.Group[0].ID
        Name = $_.Name 
        Sex = $_.Group[0].Sex
    }
    for ($i = 0; $i -lt $_.Group.Count; $i++) {

        $obj["Age$($i+1)"] = $_.Group[$i].Age
    }
    [PsCustomObject]$obj
} | Export-Csv 'test_output.csv' -NoTypeInformation

组合不同的列 powershell

Combining different columns powershell

csv

powershell

duplicates