如何对未来的类型使用折叠方法？

Question

我有这个方法作为我的存储库：

Future<Either<Exceptions, bool>> userRegister(FormData formData) async {
    try {
      final response = await _mourdakApi.userRegister(formData);
      bool _isSuccesed;
      if (response.statusCode == 200)
        _isSuccesed = true;
      else
        _isSuccesed = false;
      return Right(_isSuccesed);
    } catch (e) {
      return Left(
        Exceptions(
          message: e.toString(),
        ),
      );
    }
  }

现在我想在这里使用折叠方法:

final failedOrResult = _mourdakRepository.userRegister(event.formData);

return failedOrResult.fold(
      (exception) => UserExceptionState(exception.message),
      (isSuccesed) => UserRegisterState(isSuccesed));

但是我得到了这个错误：

The method 'fold' isn't defined for the type 'Future'

Answer 1

不知道有没有解决，就是少了await。另一种方法是使用在 lib dartz

中定义的 Task 方法

final failedOrResult = await _mourdakRepository.userRegister(event.formData);

return failedOrResult.fold(
      (exception) => UserExceptionState(exception.message),
      (isSuccesed) => UserRegisterState(isSuccesed));

如何对未来的类型使用折叠方法？

How to use the fold method for a future type?

flutter

future

dartz