C++ winsock 接受抛出的异常

Question

我用的是UE4 4.26.2 github源码，windows10 1909，visual studio 2019.

代码：

// 32-bit unsigned integer
typedef unsigned int        uint32;
// 64-bit unsigned integer
typedef unsigned long long  uint64;

template<typename T32BITS, typename T64BITS>
struct SelectIntPointerType<T32BITS, T64BITS, 8>
{
    // Select the 64 bit type.
    typedef T64BITS TIntPointer;
};
typedef SelectIntPointerType<uint32, uint64, sizeof(void*)>::TIntPointer UPTRINT;

UPTRINT TcpSocketListen(uint16 Port)
{
    // See TcpSocketConnect() for why WSASocket() is used here.
    SOCKET Socket = WSASocket(AF_INET, SOCK_STREAM, IPPROTO_TCP, nullptr, 0, WSA_FLAG_NO_HANDLE_INHERIT);

    sockaddr_in SockAddr;
    SockAddr.sin_family = AF_INET;
    SockAddr.sin_addr.s_addr = 0;
    SockAddr.sin_port = htons(Port);
    int Result = bind(Socket, (SOCKADDR*)&SockAddr, sizeof(SockAddr));
    Result = listen(Socket, 1);
    if (!TcpSocketSetNonBlocking(Socket, 1))
    {
        closesocket(Socket);
        return 0;
    }

    return UPTRINT(Socket) + 1;
}

////////////////////////////////////////////////////////////////////////////////
int32 TcpSocketAccept(UPTRINT Socket, UPTRINT& Out)
{
    SOCKET Inner = Socket - 1;

    Inner = accept(Inner, nullptr, nullptr);

}

static UPTRINT          GControlListen      = 0;
GControlListen = TcpSocketListen(1985);
UPTRINT Socket;
int Return = TcpSocketAccept(GControlListen, Socket);

调试时，visual studio在 line:accept(内部, nullptr, nullptr);

输出：在 0x00007FFCDF673B19 处抛出异常（在 UE4Editor-Win64-Debug.exe 中）：Microsoft C++ 异常：内存位置 0x0000001F892FFC38 处的 int。

最良好的祝愿，点

Answer 1

accept 上的套接字文档：

The argument sockfd is a socket that has been created with socket(2), bound to a local address with bind(2), and is listening for connections after a listen(2).

所以第一个参数必须只是一个套接字描述符。您正在将该套接字转换为指针，将地址加 1，这将完全改变套接字中返回值的值。然后传递该数字以接受并减去一个。套接字库不知道该数字的含义并崩溃。

只需在后续调用中使用从套接字库返回的原始值。

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