如何将 uint256 变量转换为 int256 变量?
How do I convert a uint256 variable to an int256 one?
我试图通过在 return price;
正下方键入 return timeStamp;
来打印 uint timeStamp
代码:
pragma solidity ^0.6.7;
import "@chainlink/contracts/src/v0.6/interfaces/AggregatorV3Interface.sol";
contract PriceConsumerV3 {
AggregatorV3Interface internal priceFeed;
/**
* Network: Kovan
* Aggregator: BTC/USD
* Address: 0x6135b13325bfC4B00278B4abC5e20bbce2D6580e
*/
constructor() public {
priceFeed = AggregatorV3Interface(0x6135b13325bfC4B00278B4abC5e20bbce2D6580e);
}
/**
* Returns the latest price
*/
function getThePrice() public view returns (int) {
(
uint80 roundID,
int price,
uint startedAt,
uint timeStamp,
uint80 answeredInRound
) = priceFeed.latestRoundData();
return price;
return timeStamp;
}
}
当我在 Remix Compiler 上编译上面的代码时,它回答:
TypeError: Return argument type uint256 is not implicitly convertible to expected type (type of first return variable) int256. return timeStamp; ^-------^
我倾向于认为我只需要输入 int256 return timeStamp
或类似的东西而不是 return timeStamp;
但我想不通。
欢迎反馈。
您可以使用以下语法将 uint
类型转换为 int
:
return int(timeStamp);
注意:对于 2^255-1
(int
最大值)和 2^256-1
(uint
最大值)。但这很可能只是一个理论案例,因为时间戳预计不会有这么大的值。
请注意,此行无法访问,因为您已经 returning price
上一行。
(
uint80 roundID,
int price,
uint startedAt,
uint timeStamp,
uint80 answeredInRound
) = priceFeed.latestRoundData();
return price; // the `price` is returned, and the function doesn't execute after this line
return timeStamp; // this is ignored because of the early return on previous line
如果你想return多个值,你可以使用这个语法:
// note the multiple datatypes in the `returns` block
function getThePriceAndTimestamp() public view returns (int, uint) {
(
uint80 roundID,
int price,
uint startedAt,
uint timeStamp,
uint80 answeredInRound
) = priceFeed.latestRoundData();
return (price, timeStamp); // here returning multiple values
}
我试图通过在 return price;
正下方键入 return timeStamp;
来打印 uint timeStamp
代码:
pragma solidity ^0.6.7;
import "@chainlink/contracts/src/v0.6/interfaces/AggregatorV3Interface.sol";
contract PriceConsumerV3 {
AggregatorV3Interface internal priceFeed;
/**
* Network: Kovan
* Aggregator: BTC/USD
* Address: 0x6135b13325bfC4B00278B4abC5e20bbce2D6580e
*/
constructor() public {
priceFeed = AggregatorV3Interface(0x6135b13325bfC4B00278B4abC5e20bbce2D6580e);
}
/**
* Returns the latest price
*/
function getThePrice() public view returns (int) {
(
uint80 roundID,
int price,
uint startedAt,
uint timeStamp,
uint80 answeredInRound
) = priceFeed.latestRoundData();
return price;
return timeStamp;
}
}
当我在 Remix Compiler 上编译上面的代码时,它回答:
TypeError: Return argument type uint256 is not implicitly convertible to expected type (type of first return variable) int256. return timeStamp; ^-------^
我倾向于认为我只需要输入 int256 return timeStamp
或类似的东西而不是 return timeStamp;
但我想不通。
欢迎反馈。
您可以使用以下语法将 uint
类型转换为 int
:
return int(timeStamp);
注意:对于 2^255-1
(int
最大值)和 2^256-1
(uint
最大值)。但这很可能只是一个理论案例,因为时间戳预计不会有这么大的值。
请注意,此行无法访问,因为您已经 returning price
上一行。
(
uint80 roundID,
int price,
uint startedAt,
uint timeStamp,
uint80 answeredInRound
) = priceFeed.latestRoundData();
return price; // the `price` is returned, and the function doesn't execute after this line
return timeStamp; // this is ignored because of the early return on previous line
如果你想return多个值,你可以使用这个语法:
// note the multiple datatypes in the `returns` block
function getThePriceAndTimestamp() public view returns (int, uint) {
(
uint80 roundID,
int price,
uint startedAt,
uint timeStamp,
uint80 answeredInRound
) = priceFeed.latestRoundData();
return (price, timeStamp); // here returning multiple values
}