如何将 java 个对象列表转换为 Map<String, Map<String, String>>

Question

我有一个包含 java 个对象的列表，如下所示：

[
  {
    id: "frwfhfijvfhviufhbviufg",
    country_code: "DE",
    message_key: "key1",
    translation: "This is the deutsch translation"
  },
  {
    id: "dfregregtegetgetgttegt",
    country_code: "GB",
    message_key: "key1",
    translation: "This is the uk translation"
  },
  {
    id: "frffgfbgbgbgbgbgbgbgbg",
    country_code: "DE",
    message_key: "key2",
    translation: "This is the again deutch translation"
  }
]

如何将其转换为如下所示的 Map<String, Map<String, String>>：

{
  "DE": {
    "key1": "This is the deutsch translation",
    "key2": "This is the again deutch translation"
  },
  "GB": {
    "key1": "This is the uk translation"
  }
}

我是 java 的新手，下面是我的代码，但代码不正确：

Map<String, Translations> distinctTranslations = customTranslationsEntities
        .stream().collect(Collectors.groupingBy(
                CustomTranslationsEntity::getCountryCode,
                Collectors.toMap(
                        CustomTranslationsEntity::getMessageKey,
                        CustomTranslationsEntity::getTranslation),

                )))

其中 Translations 是原始缓冲区消息，如下所示：

message Translations {
  map<string, string> translations = 1;
}

这里map<string, string> translations表示地图像"key1", "This is the deutsch translation"...像这样。

Answer 1

输出应该是Map<String, Map<String,String>>:

Map<String, Map<String,String>>
    distinctTranslations = customTranslationsEntities
            .stream()
            .collect(Collectors.groupingBy(CustomTranslationsEntity::getCountryCode,
                                    Collectors.toMap(
                                            CustomTranslationsEntity::getMessageKey,
                                            CustomTranslationsEntity::getTranslation,
                                            (v1,v2)->v1)));

我添加了合并功能，以防出现重复键。

Answer 2

如果你想在不使用流的情况下做到这一点，那么

private List<MyObject> list = // Your object List
private Map<String, Map<String, String>> map = new HashMap<>();

for(MyObject object : list){
    Map<String, String> localMap;
    localMap = map.getOrDefault(object.country_code, new HashMap<>());
    localMap.put(object.message_key, object.translation);
    if(!map.containsKey(object.country_code)){
        map.put(object.country_code, localMap);
    }
}