Class 删除了拷贝构造函数还能拷贝吗?

Class with a deleted copy constructor can be still copied?

我有一个简单的功能: void foo(atomic<int> a) { }

碰巧我可以这样调用foo()foo({ }); 但我不能这样做: foo(atomic<int>{ }); 由于错误消息 copy constructor is a deleted function。我已经用 C++14 编译了。

  1. 第一种方式调用什么构造函数:创建构造函数还是移动构造函数?
  2. 为什么第二种方式不调用移动构造函数?
  3. foo() 的这两个调用在 C++17 中编译良好 - 为什么?

foo({ });中,参数为copy list-initialized。结果它由 std::atomic.

的默认构造函数初始化

foo(atomic<int>{ });中,参数为copy-initialized from the temporary std::atomic (i.e. atomic<int>{ }). Before C++17 even the copy/move operation might be elided the copy/move constructor still has to be present and accessible. Since C++17 this is not required again because of mandatory copy elision,保证参数直接由std::atomic的默认构造函数初始化。

First, if T is a class type and the initializer is a prvalue expression whose cv-unqualified type is the same class as T, the initializer expression itself, rather than a temporary materialized from it, is used to initialize the destination object: see copy elision (since C++17)

Under the following circumstances, the compilers are required to omit the copy and move construction of class objects, even if the copy/move constructor and the destructor have observable side-effects. The objects are constructed directly into the storage where they would otherwise be copied/moved to. The copy/move constructors need not be present or accessible: (since C++17)