一旦我们在 SwiftUI iOS 中获得 openurl，如何关闭 SFSafariviewcontroller？

Question

我正在开发 SwiftUI 应用程序，我正在导航到 SFSafariviewcontroller（浏览器），一旦登录完成，我将获得 openurl。

我想在获得 openurl 后自动关闭 SFSafariviewcontroller。

感谢您的帮助...以下是我的工作

//how I am calling Safari 
     .fullScreenCover(isPresented: $isButtonActive, content: {
                    if let url = loginAction() {
                        SafariView(url: url)
                        
                    }
                }


//how i am getting openurl
    @main
    struct MyApplication: App {
      var body: some Scene {
        WindowGroup {
          ContentView()
            .onOpenURL { url in
              // handle the URL that must be opened
            }
        }
      }
    }

我的 safari 代码

import SafariServices

struct Myview: View {
    
    @EnvironmentObject var appConfiguration : AppConfiguration
    @State private var isButtonActive = true
    @State private var isLoginActive = true

    var body: some View {
        NavigationView {
                    Button( buttonTitle: "button" buttonCallback: {
                        self.isLoginActive = true
                    }, isActive: $isButtonActive)
                }
            }
            .afklPageView()
            .navigationBarTitle("title", displayMode: .inline)
            .fullScreenCover(isPresented: $isButtonActive, content: {
                if let url = loginAction() {
                    SafariView(url: url)

                }
            })
        
        }
            
    }

struct SafariView: UIViewControllerRepresentable {
    let url: URL
    func makeUIViewController(context: UIViewControllerRepresentableContext<Self>) -> SFSafariViewController {
        return SFSafariViewController(url: url)
    }
    func updateUIViewController(_ uiViewController: SFSafariViewController, context: UIViewControllerRepresentableContext<SafariView>) {
        
    }
}

Answer 1

这是一个基本示例，展示了如何存储 EnvironmentObject 中显示的浏览器状态：

class SafariState : ObservableObject {
    @Published var showSafari = false
}

@main struct WhosebugApp: App {
    @StateObject var safariState = SafariState()

    var body: some Scene {
        WindowGroup {
            ContentView()
                .environmentObject(safariState)
                .onOpenURL { url in
                    safariState.showSafari = false
                }
        }
    }
}

struct ContentView: View {
    @EnvironmentObject private var safariState : SafariState
    
    var body: some View {
        Button("Toggle safari") {
            safariState.showSafari.toggle()

            //include for testing to show how to dismiss it
            //DispatchQueue.main.asyncAfter(deadline: .now() + 3) {
            //    safariState.showSafari = false
            //}
        }.fullScreenCover(isPresented: $safariState.showSafari) {
            SafariView(url: URL(string: "https://google.com")!)
        }
    }
}

请注意如何使用 .environmentObject

将 SafariState 传递到视图层次结构中

一旦我们在 SwiftUI iOS 中获得 openurl，如何关闭 SFSafariviewcontroller？

How to close SFSafariviewcontroller once we get openurl in SwiftUI iOS?

ios

swiftui

sfsafariviewcontroller