如何在 PHP 更新表单中显示选中的复选框？后置 sql

Question

我必须显示选中的复选框 (like this one), but currently when extracting the value from the database (it shows this)

有没有办法在从数据库中提取已知值时显示选中的复选框 (PgAdmin)（所有代码都是 HTML、CSS 或 PHP）

代码：

 Topings: <br>
 <br>
 <label class="checkbox-container">
   <input type="checkbox" name="toping" <?php if(isset($_POST['toping']) && $_POST['toping']=="Vanilla") echo "checked" ?> value="<?php echo $row['toping']; ?>">
   <span class="checkmark"></span>
   <span class="checkbox-txt"> Vanilla</span>
   <br /></br>
 </label>
 <label class="checkbox-container">
   <input type="checkbox" name="toping" <?php if(isset($_POST['toping']) && $_POST['toping']=="Chocolate") echo "checked" ?>value="<?php echo $row['toping']; ?>">
   <span class="checkmark"></span>
   <span class="checkbox-txt">Chocolate</span>
   <br /></br>
 </label>
 <label class="checkbox-container">
   <input type="checkbox" name="toping" <?php if(isset($_POST['toping']) && $_POST['toping']=="Caramel") echo "checked" ?>value="<?php echo $row['toping']; ?>">
   <span class="checkmark"></span>
   <span class="checkbox-txt">Caramel</span>
   <br /></br>
 </label>
 <label class="checkbox-container">
   <input type="checkbox" name="toping" <?php if(isset($_POST['toping']) && $_POST['toping']=="Strawberry") echo "checked" ?>value="<?php echo $row['toping']; ?>">
   <span class="checkmark"></span>
   <span class="checkbox-txt">Strawberry</span>
   <br /></br>
 </label>
 <label class="checkbox-container">
   <input type="checkbox" name="toping" <?php if(isset($_POST['toping']) && $_POST['toping']=="M&M's") echo "checked" ?>value="<?php echo $row['toping']; ?>">
   <span class="checkmark"></span>
   <span class="checkbox-txt">M&M's</span>
   <br /></br>
 </label>
 <label class="checkbox-container">
   <input type="checkbox" name="toping" <?php if(isset($_POST['toping']) && $_POST['toping']=="Oreo") echo "checked" ?>value="<?php echo $row['toping']; ?>">
   <span class="checkmark"></span>
   <span class="checkbox-txt">Oreo</span>
   <br /></br>
 </label>
 <label class="checkbox-container">
   <input type="checkbox" name="toping" <?php if(isset($_POST['toping']) && $_POST['toping']=="Meringue") echo "checked" ?>value="<?php echo $row['toping']; ?>">
   <span class="checkmark "></span>
   <span class="checkbox-txt">Meringue</span>
   <br />
 </label>

Answer 1

首先，您必须知道如何将多个复选框值存储到数据库中。如果您需要，我已经添加了参考资料。

假设您的 toppings 保存为 逗号分隔值，如下所示：

您可以使用 explode() 函数将 逗号分隔值 分解为平面 索引数组.

从 Chocolate,Caramel,M&M's 到 ["Chocolate", "Caramel", "M&M's"]。
然后你可以使用in_array()函数来检查item(topping)是否在数组.

PHP

/* Connection with PDO */
// DB details (Change it to your DB details)
$host = '127.0.0.1';
$user = 'root';
$password = 'root';
$dbname = 'test';
$port = '3306';

// DataSourceName for MySQL (The one I used for testing)
$dsn = "mysql:dbname=$dbname;host=$host;port=$port";
// DataSourceName for PostgreSQL (Use this and add port if you need)
$dsn = 'pgsql:dbname=$dbname;host=$host;';

$pdo = new PDO($dsn, $user, $password);
/* End Connection String */

// Get Toppings Value From DB
$statement = $pdo->query("SELECT `toppings` FROM toppings");
$res = $statement->fetch();

//res[0] = Comma Separated String of Toppings: 'Topping1,Topping2,Topping3'
$toppings = explode(',', $res[0]);
// $toppings = Array of toppings checked: ["Topping1", "Topping2", "Topping3" ]


/* Connection with PG */
$db = pg_connect("host=localhost port=5432 dbname=SRIS user=postgres password=password");
$result = pg_query($db, "SELECT * FROM tablename ");
$row = pg_fetch_assoc($result);

$toppings = explode(',', $row['toppings']);

HTML 表格

<label class="checkbox-container">
  <input type="checkbox" name="toping[]" <?=(in_array('Vanilla',$toppings) ? 'checked="checked"' : '')?> value="Vanilla">
  <span class="checkmark"></span>
  <span class="checkbox-txt"> Vanilla</span><br/></br>
</label>
<label class="checkbox-container">
    <input type="checkbox" name="toping[]" <?=(in_array('Chocolate',$toppings) ? 'checked="checked"' : '')?> value="Chocolate">
    <span class="checkmark"></span>
    <span class="checkbox-txt">Chocolate</span><br/></br>
</label>
<label class="checkbox-container">
    <input type="checkbox" name="toping[]" <?=(in_array('Caramel',$toppings) ? 'checked="checked"' : '')?> value="Caramel">
    <span class="checkmark"></span>
    <span class="checkbox-txt">Caramel</span><br/></br>
</label>
<label class="checkbox-container">
    <input type="checkbox" name="toping[]" <?=(in_array('Strawberry',$toppings) ? 'checked="checked"' : '')?> value="Strawberry">
    <span class="checkmark"></span>
    <span class="checkbox-txt">Strawberry</span><br/></br>
</label>
<label class="checkbox-container">
    <input type="checkbox" name="toping[]" <?=(in_array("M&M's",$toppings) ? 'checked="checked"' : '')?> value="M&M's">
    <span class="checkmark"></span>
    <span class="checkbox-txt">M&M's</span><br/></br>
</label>
<label class="checkbox-container">
    <input type="checkbox" name="toping[]" <?=(in_array('Oreo',$toppings) ? 'checked="checked"' : '')?> value="Oreo">
    <span class="checkmark"></span>
    <span class="checkbox-txt">Oreo</span><br/></br>
</label>
<label class="checkbox-container">
    <input type="checkbox" name="toping[]" <?=(in_array('Meringue',$toppings) ? 'checked="checked"' : '')?> value="Meringue">
    <span class="checkmark "></span>
    <span class="checkbox-txt">Meringue</span><br/>
</label>

注:

我已经将 name 属性更改为 name=topping[]，你应该使用 field name array.
我还更改了 value 属性，为每个复选框提供了 预定值。

参考文献：

爆炸：Comma-delimited string into an array?
<?= : What does '<?=' means in PHP
将复选框值存储到数据库的示例：How to Insert Multiple Checkbox Value to Database

如何在 PHP 更新表单中显示选中的复选框？后置 sql

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