Angular 11 从 URL 获取参数

Question

我想从我的 url 中获取参数。我的路线结构为

{
    path: 'customers/viewCustomer/:id',component:CommonSingleCustomerPageComponent, canActivate: [AuthGuard], data:{ permission:['Manage-Customer']},
    children: [
      {
        path: 'detail',
        component: ViewCustomerComponent, canActivate: [AuthGuard],data:{permission: ['Manage-Customer']}
      },
}

但是当我尝试获取 ViewCustomerComponent 中的 :id 时，我发现它是未定义的。我试过以下方法：

    export class ViewCustomerComponent implements OnInit {
    constructor(
            private router: ActivatedRoute,
          ) { }
        
          data: any = '';
          id: any = '';
        
          ngOnInit(): void {
            this.id = this.router.snapshot.params.id
            console.log(this.id)
    }
    }

还有，

export class ViewCustomerComponent implements OnInit {

  constructor(
    private router: ActivatedRoute,
  ) { }

  data: any = '';
  id: any = '';

  ngOnInit(): void {
    this.id = this.router.snapshot.paramMap.get('id')
    console.log(this.id)
  }
}

但是 none 这些作品。知道我做错了什么吗？

Answer 1

您想访问在父级中定义的路径路由。所以使用父对象访问子组件 ViewCustomerComponent

中的值 (:id)

this.router.parent.params

或参考这篇文章 https://ultimatecourses.com/blog/angular-parent-routing-params

Angular 11 从 URL 获取参数

Angular 11 get params from URL

node.js

angular

typescript

router