在 swift 5 中将字符串转换为字典？

Question

我有一个包含 json 的字符串，格式如下：

var myString: String = "{key1: val1, key2: val2}"

如何将其转换为：

var myJson: [String: String] = ["key1": "val1", "key2": "val2"]

由于我的字符串不是 "{"key1": "val1", "key2": "val2"}" 格式，我在通过以下代码片段解析它时遇到了困难：

func convertToDictionary(text: String) -> [String: Any]? {
    if let data = text.data(using: .utf8) {
        do {
            return try JSONSerialization.jsonObject(with: data, options: []) as? [String: Any]
        } catch {
            print(error.localizedDescription)
        }
    }
    return nil
}

这个函数对于 myString

总是 returns nil

Answer 1

你可能不得不以艰难的方式去做。像这样：

import SwiftUI

@main
struct TestApp: App {
    var body: some Scene {
        WindowGroup {
            ContentView()
        }
    }
}

extension String {
    func trim() -> String {
        return self.trimmingCharacters(in: .whitespacesAndNewlines)
    }
}

struct ContentView: View {
    var body: some View {
        Text("testing")
            .onAppear {
                let myString: String = "{key1: val1, key2: val2, key3: val3}"
                let myJson = transform(myString)
                print("----> myJson: \(myJson)")
            }
    }
    
    func transform(_ myString: String) -> [String : String] {
        var result = [String : String]()
        if myString.count > 2 { // case of {}
            let temp1 = myString.dropFirst().dropLast()
            let temp2 = temp1.split(separator: ",").map{String([=10=])}
            for str in temp2 {
                let temp3 = str.split(separator: ":").map{String([=10=])}
                let (k,v) = (temp3[0].trim(),temp3[1].trim())
                result[k] = v
            }
        }
        return result
    }
}

Answer 2

您知道应该引用键和值。这是一个简单的方法。

let jsonString = myString.replacingOccurrences(of: "(\w+)", with: "\"\"", options: .regularExpression)

let result = convertToDictionary(text: jsonString)

在 swift 5 中将字符串转换为字典？

convert string to dictionary in swift 5?

swift

string

nsdictionary

swift5