为什么这个 find 方法返回 None 并抛出错误？

Question

import requests
from bs4 import BeautifulSoup
import re
import pandas as pd

def tableData(data, attrs):
    row = []
    
    data = data.find(attrs=attrs)
    tr = data.find_all('tr')
    header = [ th.get_text(strip=True) for th in data.find_all('th') ]
    if header:
        row.append(header)
    for tr in tr[1:]:
        row.append([ td.get_text(strip=True) for td in tr.find_all('td')])
    return row

url1 = 'https://www.nfl.com/standings/league/2019/REG'
page1 = requests.get(url1)
soup1 = BeautifulSoup(page1.text, 'lxml')
table = soup1.find('table', attrs={'summary': 'Standings - Detailed View'})
# print(table)
print(tableData(table, {'summary': 'Standings - Detailed View'}))

即使在调试器中我也看到数据的值包含 Standings - 详细视图 但是当 data.find(attrs=attrs) 是运行时似乎 return None

Answer 1

您已经拥有 table：table。它有行和一切，但它没有任何进一步的“排名 - 详细视图”属性。直接进入行：

def tableData(data):#, attrs):
    row = []    
    #data = data.find(attrs=attrs)
    tr = data.find_all('tr')

更好的是，使用 pandas（无论如何导入它）将 table 提取为数据框：

df = pd.read_html('https://www.nfl.com/standings/league/2019/REG')[0]

为什么这个 find 方法返回 None 并抛出错误？

why is this find method returning None and throwing error?

beautifulsoup

request

python-3.x

python-requests