Select 然后为每个结果插入

Question

我有这个table:

Table name: `user_offer_rels`
+----+--------+--------+-------+
| ID | userID | permID | state |
+----+--------+--------+-------+
| 1  | 1      | 1      | 0     |
| 2  | 1      | 2      | 0     |
| 3  | 2      | 1      | 0     |
| 4  | 2      | 2      | 0     |
+----+--------+--------+-------+

我想为这个查询的每个结果插入一条新记录：

SELECT DISTINCT userID FROM `user_offer_rels`

The results:
+--------+
| userID |
+--------+
| 1      |
| 2      |
+--------+

因此，对于每个用户 ID，我都需要做这样的事情：

INSERT INTO `user_offer_rels` (userID, permID, state) VALUES (`the userID record from above`, 4, 0)

我的记录太多，无法一一插入。

编辑：

运行此 INSERT 后 user_offer_rels table 的预期结果：

+----+--------+--------+-------+
| ID | userID | permID | state |
+----+--------+--------+-------+
| 1  | 1      | 1      | 0     |
| 2  | 1      | 2      | 0     |
| 3  | 2      | 1      | 0     |
| 4  | 2      | 2      | 0     |
| 5  | 1      | 4      | 0     |
| 6  | 2      | 4      | 0     |
+----+--------+--------+-------+

Answer 1

而不是 INSERT ... VALUES ... 使用 INSERT ... SELECT ...

INSERT INTO user_offer_rels (userID, permID, state) 
SELECT DISTINCT userID, 4, 0
FROM user_offer_rels

参见demo。

Answer 2

您可以使用 select 作为插入语句

CREATE TABLE user_offer_rels
    (`ID` int AUTO_INCREMENT PRIMARY KEY , `userID` int, `permID` int, `state` int)
;
    
INSERT INTO user_offer_rels
    (`ID`, `userID`, `permID`, `state`)
VALUES
    (1, 1, 1, 0),
    (2, 1, 2, 0),
    (3, 2, 1, 0),
    (4, 2, 2, 0)

INSERT INTO user_offer_rels (`userID`, `permID`, `state`)  SELECT DISTINCT userID,4, 0 FROM user_offer_rels

SELECT * FROM user_offer_rels

ID | userID | permID | state
-: | -----: | -----: | ----:
 1 |      1 |      1 |     0
 2 |      1 |      2 |     0
 3 |      2 |      1 |     0
 4 |      2 |      2 |     0
 5 |      1 |      4 |     0
 6 |      2 |      4 |     0

db<>fiddle here

Select 然后为每个结果插入

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