保留不同的键和连接列

Question

我有一个table翻译例如：

|     key        |    language    |    value
----------------------------------------------
|       hi       |      en        |    hello
|       hi       |      es        |    hola
|       delete   |      en        |    value
|       delete   |      es        |    suprimir
|       city     |      en        |    
|       city     |      es        |    ciudad

目前有 2 种语言，但我稍后会添加更多。我正在尝试查找 sql 查询哪个组 "key" AND concat "language" 不为空值。

我正在寻找这个输出：

|    key    |   languages   |     translated
---------------------------------------------------
|    hi     |     en,es     |       100%
|   delete  |     en,es     |       100%
|    city   |     es        |       50%

有什么想法吗？

Answer 1

Group_concat 值并返回自身计算字段：

SELECT key,languages,translated_values/COUNT(key) translated
FROM table b 
INNER JOIN 
(SELECT key, GROUP_CONCAT( languages SEPARATOR ',') languages, 
COUNT(*) as translated_values 
FROM table 
WHERE translated!=""
GROUP BY key) a ON a.key=b.key
GROUP BY key,translated_values,b.languages;

Answer 2

您可以在单个查询中这样做

select `key`,
group_concat(
  case when `value` is not null 
  then `language` 
  else null end) languages,
concat(
  (sum(`value` is not null )/ count(distinct `language`) ) * 100,
  '%') translated
from table1
group by `key`

DEMO

保留不同的键和连接列

keep distinct key and concat column

mysql

group-concat