在 android 中获取和 select 个联系人

Question

我正在尝试获取所有联系人并 select 它。

我已完成获取 phone 中的所有联系人。但是当我尝试 select 一些联系人并获取他们的姓名或号码时，我遇到了空指针错误。

public class ContactListFragment extends ListFragment implements LoaderCallbacks<Cursor> {

private CursorAdapter mAdapter;
final HashMap<String,String> hashMap = new HashMap<String,String>();
Uri uri = ContactsContract.CommonDataKinds.Phone.CONTENT_URI;
private Uri uriContact;

private String contactID;
String[] projection    = new String[] {ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME,
        ContactsContract.CommonDataKinds.Phone.NUMBER};


@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    // create adapter once
    Context context = getActivity();
    int layout = android.R.layout.simple_list_item_multiple_choice;
    Cursor c = null; // there is no cursor yet
    int flags = 0; // no auto-requery! Loader requeries.
    mAdapter = new SimpleCursorAdapter(context, layout, c, FROM, TO, flags);
}



@Override
public void onActivityCreated(Bundle savedInstanceState) {
    super.onActivityCreated(savedInstanceState);

    // each time we are started use our listadapter
    setListAdapter(mAdapter);
    getListView().setChoiceMode(ListView.CHOICE_MODE_MULTIPLE);

    // and tell loader manager to start loading
    getLoaderManager().initLoader(0, null, this);

    ***getListView().setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
            Cursor cursorID = getActivity().getContentResolver().query(uriContact,
                    new String[]{ContactsContract.Contacts._ID},
                    null, null, null);
            contactID = cursorID.getString(cursorID.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
            System.out.println(contactID);
        }
    });
}***

// columns requested from the database
private static final String[] PROJECTION = {
        Contacts._ID, // _ID is always required
        Contacts.DISPLAY_NAME_PRIMARY // that's what we want to display
};

// and name should be displayed in the text1 textview in item layout
private static final String[] FROM = { Contacts.DISPLAY_NAME_PRIMARY };
private static final int[] TO = { android.R.id.text1 };

@Override
public Loader<Cursor> onCreateLoader(int id, Bundle args) {

    // load from the "Contacts table"
    Uri contentUri = Contacts.CONTENT_URI;

    // no sub-selection, no sort order, simply every row
    // projection says we want just the _id and the name column
    return new CursorLoader(getActivity(),
            contentUri,
            PROJECTION,
            null,
            null,
            null);
}

@Override
public void onLoadFinished(Loader<Cursor> loader, Cursor data) {
    // Once cursor is loaded, give it to adapter
    mAdapter.swapCursor(data);

}

@Override
public void onLoaderReset(Loader<Cursor> loader) {
    // on reset take any old cursor away
    mAdapter.swapCursor(null);
}

我认为问题出在我的 onItemClickListener 上。

我该如何解决这个问题？从现在开始感谢:)

Answer 1

主要问题是当您进行查询时 uriContact 为空。

另一个问题是您只使用 ContactsContract.Contacts._ID 作为投影，所以 ID 是唯一的 returned。

我通过使用 null 进行投影使其工作，因此它 return 所有行。

我还添加了查找当前选定联系人的功能，并显示带有他们 phone 号码的 Toast。

这不是最佳代码，因为它只查询所有行然后遍历它们直到找到当前选定的联系人，但它有效：

  getListView().setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
            Cursor cur = mAdapter.getCursor();
            cur.moveToPosition(position);
            String curName = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME_PRIMARY));
            System.out.println(curName);
            uriContact = ContactsContract.CommonDataKinds.Phone.CONTENT_URI;
            Cursor cursorID = getContentResolver().query(uriContact,
                    null,
                    null, null, null);
            for (cursorID.moveToFirst(); !cursorID.isAfterLast(); cursorID.moveToNext() ) {
                String testName = cursorID.getString(cursorID.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME_PRIMARY));
                if (testName != null && testName.equals(curName)) {
                    contactID = cursorID.getString(cursorID.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                }
            }
            if (contactID != null) {
                System.out.println(contactID);
                Toast.makeText(MainActivity.this, "contact Phone: " + contactID, Toast.LENGTH_LONG).show();
            }
        }
    });

编辑：我得到了一个更优化的版本，它在查询中使用 selection 和 selectionArgs return 只是当前的联系信息：

  getListView().setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
            Cursor cur = mAdapter.getCursor();
            cur.moveToPosition(position);
            String curName = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME_PRIMARY));
            System.out.println(curName);
            uriContact = ContactsContract.CommonDataKinds.Phone.CONTENT_URI;
            Cursor cursorID = getContentResolver().query(uriContact,
                    null,
                    ContactsContract.Contacts.DISPLAY_NAME_PRIMARY + " = ?", new String[]{curName}, null);
            if (cursorID.moveToFirst()) {
                contactID = cursorID.getString(cursorID.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
            }
            if (contactID != null) {
                System.out.println(contactID);
                Toast.makeText(MainActivity.this, "contact Phone: " + contactID, Toast.LENGTH_LONG).show();
            }
        }
    });

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