Java 代码因 "Cannot convert from void to int" 错误而无法运行

Question

我刚开始在大学学习 java 的基础知识，并且正在研究一个项目，每个玩家 return 6 个随机骰子，但我在最后一行遇到了这个错误“resultRoll = JOptionPane ...”任何帮助将不胜感激。

public class Dice {
  public static void main(String[] args){
  }
        Dice () {
            Component f = new JFrame();
        
        Random rnd = new Random();
        String resultRoll;

        // values set 1 to 6
        int n1 = 1 + rnd.nextInt(7-1);
        int n2 = 1 + rnd.nextInt(7-1);
        int n3 = 1 + rnd.nextInt(7-1);
        int n4 = 1 + rnd.nextInt(7-1);
        int n5 = 1 + rnd.nextInt(7-1);
        int n6 = 1 + rnd.nextInt(7-1);
        
        resultRoll = JOptionPane.showMessageDialog(f, "Yay! You rolled: " + n1 + n2 + n3 + n4 + n5 + n6);
        
    }
}

Answer 1

您可能想在显示消息之前设置 resultRoll。

resultRoll = n1 + " " + n2 + " " + n3 + " " + n4 + " " + n5 + " " + n6;
JOptionPane.showMessageDialog(f, "Yay! You rolled: " + resultRoll);

Java 代码因 "Cannot convert from void to int" 错误而无法运行

Java code not working due to "Cannot convert from void to int" error

java

dice