mariadb 查询和使用邮递员的不同输出
Different output from mariadb query and using postman
您好,我想从数据库到后端查询 return 一个 JSON 值。当我直接从数据库 (phpmyadmin) 查询它时,它工作正常并且查询 return 正确的值。但是当我使用邮递员访问它时,它 returns 不同的值(它 returns null)
这是来自 phpmyadmin 的查询结果
{
"name": "Desi Ratnaningsih",
"day": "Monday",
"schedule":
[
{"start": "10:00:00", "end": "13:00:00"},
{"start": "17:00:00", "end": "20:00:00"}
]
}
这是邮递员的结果
{
"name": "Desi Ratnaningsih",
"day": "Monday",
"schedule": null
}
这是我的查询
SELECT DISTINCT JSON_OBJECT(
'name', d.name,
'day', s.day,
'schedule', JSON_EXTRACT((
SELECT CONCAT('[', GROUP_CONCAT( JSON_OBJECT( 'start', h.start, 'end', h.end )) ,']')
FROM hours h JOIN schedules s ON h.id = s.working_hour
JOIN doctors d ON s.doctor_id = d.doctor_id WHERE d.doctor_id =1 AND s.day="Monday"),'$') ) AS data
FROM doctors d JOIN schedules s ON d.doctor_id=s.doctor_id
JOIN hours h on s.working_hour = h.id
WHERE d.doctor_id = 1 AND s.day="Monday";
这是simpler/correct吗?
SELECT JSON_OBJECT(
'name', d.name,
'day', s.day,
'schedule', JSON_ARRAYAGG( JSON_OBJECT( 'start', h.start, 'end', h.end ))
) AS data
FROM doctors d
JOIN schedules s ON d.doctor_id=s.doctor_id
JOIN hours h on s.working_hour = h.id
WHERE d.doctor_id = 1 AND s.day="Monday"
GROUP BY d.docker_id, s.day;
这需要 MariaDB-10.5。
对于早期版本,GROUP_CONCAT
方法是:
SELECT JSON_OBJECT(
'name', d.name,
'day', s.day,
'schedule', CONCAT('[', GROUP_CONCAT( JSON_OBJECT( 'start', h.start, 'end', h.end ) ) ,']')
) AS data
FROM doctors d
JOIN schedules s ON d.doctor_id=s.doctor_id
JOIN hours h on s.working_hour = h.id
WHERE d.doctor_id = 1 AND s.day="Monday"
GROUP BY d.docker_id, s.day;
您好,我想从数据库到后端查询 return 一个 JSON 值。当我直接从数据库 (phpmyadmin) 查询它时,它工作正常并且查询 return 正确的值。但是当我使用邮递员访问它时,它 returns 不同的值(它 returns null)
这是来自 phpmyadmin 的查询结果
{
"name": "Desi Ratnaningsih",
"day": "Monday",
"schedule":
[
{"start": "10:00:00", "end": "13:00:00"},
{"start": "17:00:00", "end": "20:00:00"}
]
}
这是邮递员的结果
{
"name": "Desi Ratnaningsih",
"day": "Monday",
"schedule": null
}
这是我的查询
SELECT DISTINCT JSON_OBJECT(
'name', d.name,
'day', s.day,
'schedule', JSON_EXTRACT((
SELECT CONCAT('[', GROUP_CONCAT( JSON_OBJECT( 'start', h.start, 'end', h.end )) ,']')
FROM hours h JOIN schedules s ON h.id = s.working_hour
JOIN doctors d ON s.doctor_id = d.doctor_id WHERE d.doctor_id =1 AND s.day="Monday"),'$') ) AS data
FROM doctors d JOIN schedules s ON d.doctor_id=s.doctor_id
JOIN hours h on s.working_hour = h.id
WHERE d.doctor_id = 1 AND s.day="Monday";
这是simpler/correct吗?
SELECT JSON_OBJECT(
'name', d.name,
'day', s.day,
'schedule', JSON_ARRAYAGG( JSON_OBJECT( 'start', h.start, 'end', h.end ))
) AS data
FROM doctors d
JOIN schedules s ON d.doctor_id=s.doctor_id
JOIN hours h on s.working_hour = h.id
WHERE d.doctor_id = 1 AND s.day="Monday"
GROUP BY d.docker_id, s.day;
这需要 MariaDB-10.5。
对于早期版本,GROUP_CONCAT
方法是:
SELECT JSON_OBJECT(
'name', d.name,
'day', s.day,
'schedule', CONCAT('[', GROUP_CONCAT( JSON_OBJECT( 'start', h.start, 'end', h.end ) ) ,']')
) AS data
FROM doctors d
JOIN schedules s ON d.doctor_id=s.doctor_id
JOIN hours h on s.working_hour = h.id
WHERE d.doctor_id = 1 AND s.day="Monday"
GROUP BY d.docker_id, s.day;