尝试在 MySQL 中创建 CTE 时出现语法错误
Getting a Syntax Error when Trying to Create a CTE in MySQL
代码如下：
WITH sub_query AS (Select imdp_title_id FROM movie_ratings)
这是输出：
Error Code: 1064. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1
MySQL 版本：'8.0.26'
使用的软件：MySQL Workbench 8.0
提前致谢。
使用 CTE 语法时，必须定义 CTE，然后在 DML 语句中使用该 CTE。
https://dev.mysql.com/doc/refman/8.0/en/with.html 说：
The following example defines CTEs named cte1 and cte2 in the WITH
clause, and refers to them in the top-level SELECT that follows the
WITH clause:
WITH
cte1 AS (SELECT a, b FROM table1),
cte2 AS (SELECT c, d FROM table2)
SELECT b, d FROM cte1 JOIN cte2
WHERE cte1.a = cte2.c;
这表明您在一个或多个 <cte> AS ( <subquery> ) 定义之后有一个最终的 SQL 语句。
MySQL 8.0 支持 CTE 之后的 SELECT、UPDATE 或 DELETE DML 语句。
代码如下：
WITH sub_query AS (Select imdp_title_id FROM movie_ratings)
这是输出：
Error Code: 1064. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1
MySQL 版本：'8.0.26'
使用的软件：MySQL Workbench 8.0
提前致谢。
使用 CTE 语法时，必须定义 CTE，然后在 DML 语句中使用该 CTE。
https://dev.mysql.com/doc/refman/8.0/en/with.html 说：
The following example defines CTEs named cte1 and cte2 in the WITH clause, and refers to them in the top-level SELECT that follows the WITH clause:
WITH cte1 AS (SELECT a, b FROM table1), cte2 AS (SELECT c, d FROM table2) SELECT b, d FROM cte1 JOIN cte2 WHERE cte1.a = cte2.c;
这表明您在一个或多个 <cte> AS ( <subquery> ) 定义之后有一个最终的 SQL 语句。
MySQL 8.0 支持 CTE 之后的 SELECT、UPDATE 或 DELETE DML 语句。