preg_match_all 使用 php preg_match_all 从 httpd-vhosts.conf 文件 xampp 获取虚拟主机列表

preg_match_all to get list of virtual hosts from httpd-vhosts.conf file xampp using php preg_match_all

这是我试过的,我也不想要用#/##评论的主机和解释

$str = '# Virtual Hosts
#
# Required modules: mod_log_config

# If you want to maintain multiple domains/hostnames on your
# machine you can setup VirtualHost containers for them. Most configurations
# use only name-based virtual hosts so the server doesn\'t need to worry about
# IP addresses. This is indicated by the asterisks in the directives below.
#
# Please see the documentation at 
# <URL:http://httpd.apache.org/docs/2.4/vhosts/>
# for further details before you try to setup virtual hosts.
#
# You may use the command line option \'-S\' to verify your virtual host
# configuration.

#
# Use name-based virtual hosting.
#
##NameVirtualHost *:80
#
# VirtualHost example:
# Almost any Apache directive may go into a VirtualHost container.
# The first VirtualHost section is used for all requests that do not
# match a ##ServerName or ##ServerAlias in any <VirtualHost> block.
#
##<VirtualHost *:80>
    ##ServerAdmin webmaster@dummy-host.example.com
    ##DocumentRoot "D:/xampp/htdocs/dummy-host.example.com"
    ##ServerName dummy-host.example.com
    ##ServerAlias www.dummy-host.example.com
    ##ErrorLog "logs/dummy-host.example.com-error.log"
    ##CustomLog "logs/dummy-host.example.com-access.log" common
##</VirtualHost>

##<VirtualHost *:80>
    ##ServerAdmin webmaster@dummy-host2.example.com
    ##DocumentRoot "D:/xampp/htdocs/dummy-host2.example.com"
    ##ServerName dummy-host2.example.com
    ##ErrorLog "logs/dummy-host2.example.com-error.log"
    ##CustomLog "logs/dummy-host2.example.com-access.log" common
##</VirtualHost>



##<VirtualHost *:8080>
    ##ServerName CI1
    ##DocumentRoot D:\xampp\htdocs\codeigniter_1\public
##</VirtualHost>

<VirtualHost *:8080>
    ServerName CI2
    DocumentRoot D:\xampp\htdocs\codeigniter_2\public
</VirtualHost>

<VirtualHost *:8080>
    ServerName CI3
    DocumentRoot D:\xampp\htdocs\codeigniter_3\public
</VirtualHost>';

模式 1

$pattern1 = "#<\s*?$tagname\b[^>]*>(.*?)</$tagname\b[^>]*>#s";
preg_match_all($pattern1, $str, $match);

模式 2

$pattern2 = "/^(?<!#).*<$tagname.*>(.+?)<\/tagname>/mis";
preg_match_all($pattern2, $str, $matches);

函数

function everything_in_tags($str, $tagname)
{
    $pattern1 = "#<\s*?$tagname\b[^>]*>(.*?)</$tagname\b[^>]*>#s";
    preg_match_all($pattern1, $str, $match);
    
    $pattern2 = "/^(?<!#).*<$tagname.*>(.+?)<\/$tagname>/s";
    preg_match_all($pattern2, $str, $matches);
    
    echo '<pre>',print_r($match[1]),'</pre>';
    
    echo '<pre>',print_r($matches[1]),'</pre>';
}

everything_in_tags($str, $tagname);

模式 1 的输出

Array
(
    [0] =>  block.
#
##
    ##ServerAdmin webmaster@dummy-host.example.com
    ##DocumentRoot "D:/xampp/htdocs/dummy-host.example.com"
    ##ServerName dummy-host.example.com
    ##ServerAlias www.dummy-host.example.com
    ##ErrorLog "logs/dummy-host.example.com-error.log"
    ##CustomLog "logs/dummy-host.example.com-access.log" common
##
    [1] => 
    ##ServerAdmin webmaster@dummy-host2.example.com
    ##DocumentRoot "D:/xampp/htdocs/dummy-host2.example.com"
    ##ServerName dummy-host2.example.com
    ##ErrorLog "logs/dummy-host2.example.com-error.log"
    ##CustomLog "logs/dummy-host2.example.com-access.log" common
##
    [2] => 
    ##ServerName CI1
    ##DocumentRoot D:\xampp\htdocs\codeigniter_1\public
##
    [3] => 
    ServerName CI2
    DocumentRoot D:\xampp\htdocs\codeigniter_2\public

    [4] => 
    ServerName CI3
    DocumentRoot D:\xampp\htdocs\codeigniter_3\public

)

模式 2 的输出

Array
(
    [0] => 
    ServerName CI3
    DocumentRoot D:\xampp\htdocs\codeigniter_3\public

)

期望的输出

Array
(
    [0] => array(
        [ServerName] : CI2
        [DocumentRoot] : D:\xampp\htdocs\codeigniter_2\public
        ),
    [1] => array(
        [ServerName] : CI3
        [DocumentRoot] : D:\xampp\htdocs\codeigniter_3\public
        );
)

任何帮助将不胜感激,因为我是正则表达式的新手.....我也不需要任何用#/##注释的字符串,提前致谢..

用作正则表达式:

'~^\s*<VirtualHost\s+[^>]*>\s*ServerName\s+(?P<ServerName>\S+)\s*DocumentRoot\s+(?P<DocumentRoot>\S+)\s*</VirtualHost>~m'

然后你需要的将在捕获组 1/'ServerName' 和 2/'DocumentRoot'.

解释:

  1. ^ - 匹配设置了 m 标志的行首。
  2. \s* - 匹配 0 个或多个空白字符。
  3. <VirtualHost - 匹配“
  4. \s+ - 匹配 1 个或多个空白字符。
  5. [^>]* 匹配 0 个或多个不是 '>' 的字符。
  6. > - 匹配'>'。
  7. \s* - 匹配 0 个或多个空白字符。
  8. ServerName - 匹配 'ServerName'.
  9. \s+ - 匹配1个或多个空白字符,
  10. (?P<ServerName>\S+) - 匹配 1 个或多个非空白字符作为捕获组 'ServerName'.
  11. \s* - 匹配 0 个或多个空白字符。
  12. DocumentRoot - 匹配 'DocumentRoot'.
  13. \s+ - 匹配1个或多个空白字符,
  14. (?P<DocumentRoot>\S+) - 匹配 1 个或多个非空白字符作为捕获组 'DocumentRoot'.
  15. \s* - 匹配 0 个或多个空白字符。
  16. </VirtualHost> - 匹配“”。

See RegEx Demo

代码:

$regex = '^\s*<VirtualHost\s+[^>]*>\s*ServerName\s+(?P<ServerName>\S+)\s*DocumentRoot\s+(?P<DocumentRoot>\S+)\s*</VirtualHost>~m';
preg_match_all($regex, $str, $matches, PREG_SET_ORDER);
print_r($matches);

打印:

Array
(
    [0] => Array
        (
            [0] =>
<VirtualHost *:8080>
    ServerName CI2
    DocumentRoot D:\xampp\htdocs\codeigniter_2\public
</VirtualHost>
            [ServerName] => CI2
            [1] => CI2
            [DocumentRoot] => D:\xampp\htdocs\codeigniter_2\public
            [2] => D:\xampp\htdocs\codeigniter_2\public
        )

    [1] => Array
        (
            [0] =>
<VirtualHost *:8080>
    ServerName CI3
    DocumentRoot D:\xampp\htdocs\codeigniter_3\public
</VirtualHost>
            [ServerName] => CI3
            [1] => CI3
            [DocumentRoot] => D:\xampp\htdocs\codeigniter_3\public
            [2] => D:\xampp\htdocs\codeigniter_3\public
        )

)

更新

以上正则表达式假定 DocumentRoot 规范不包含嵌入空格,但情况可能并非总是如此。它还有一个多余的、不必要的 s*,我已将其删除。我相信以下正则表达式是一种改进。它将匹配 1 个或多个非空白字符的 \S+ 替换为 .+?,这将 非贪婪地 匹配 1 个或多个 any 字符(换行符除外)。因为它后面跟着 \s*</VirtualHost>,是 非贪婪的 ,一旦它发现 ' 可选地前面有任何空格,它就会停止匹配。

所以新的正则表达式将是(与 m 标志一起使用):

^\s*<VirtualHost\s+[^>]*>\s*ServerName\s+(?P<ServerName>\S+)\s*DocumentRoot\s+(?P<DocumentRoot>.+?)\s*</VirtualHost>

See new RegEx Demo

$regex = '^\s*<VirtualHost\s+[^>]*>\s*ServerName\s+(?P<ServerName>\S+)\s*DocumentRoot\s+(?P<DocumentRoot>.+?)\s*</VirtualHost>~m';
preg_match_all($regex, $str, $matches, PREG_SET_ORDER);
print_r($matches);