打印特定组合

Question

我一直在做一些组合程序，目前，我想做的是通过以下技术完成的：

from itertools import combinations

item_1 = [1,2,3,4,5,6,8,7]
item_2 = [10,12,14,15,16,17,19]
item_3 = [21,22,23,27,25,29]
item_4 = [32,33,36,37,38,39]
item_5 = [42,43,45,46,47,49]
item_6 = [51,52,53,57,59]
item_7 = [61,62,68]
item_8 = [71,72,75,78,79]

all_lists = item_1 + item_2 + item_3 + item_4 + item_5 + item_6 + item_7 + item_8

for (a,b,c,d,e,f,g,h) in combinations(all_lists, 8):
    print((a,b,c,d,e,f,g,h))

OUTPUT:
(1, 2, 3, 22, 25, 32, 39, 45)
(1, 2, 3, 22, 25, 32, 39, 46)
(1, 2, 3, 22, 25, 32, 39, 47)
(1, 2, 3, 22, 25, 32, 39, 49)
(1, 2, 3, 22, 25, 32, 39, 51)
(1, 2, 3, 22, 25, 32, 39, 52)
(1, 2, 3, 22, 25, 32, 39, 53)
(1, 2, 3, 22, 25, 32, 39, 57)

不过，我不需要包含重叠的项目，例如：

item_1 = [1,2,3,4,5,6,8,7] should all stay in the 'a' variable

item_2 = [10,12,14,15,16,17,19] should all stay in the 'b' variable

item_3 = [21,22,23,27,25,29] should all stay in the 'c' variable

我只是想查看所有组合，但将每个列表保存在单独的字母中，但现在它正在检查所有列表的组合，因为我将它们加在一起以使 combinations() 函数起作用.

有没有办法或其他 itertools 函数来完成我想要实现的目标？

Answer 1

我认为你在追求 product。

from itertools import product

item_1 = [1,2,3,4,5,6,8,7]
item_2 = [10,12,14,15,16,17,19]
item_3 = [21,22,23,27,25,29]
item_4 = [32,33,36,37,38,39]
item_5 = [42,43,45,46,47,49]
item_6 = [51,52,53,57,59]
item_7 = [61,62,68]
item_8 = [71,72,75,78,79]

all_lists = [item_1, item_2, item_3, item_4, item_5, item_6, item_7, item_8]

for (a,b,c,d,e,f,g,h) in product(*all_lists):
    print((a,b,c,d,e,f,g,h))

打印特定组合

Printing specific combinations

python

combinations

itertools