atoi 和 strtol 产生错误的结果

Question

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main() {
    char *filename = "Sayilar.txt";
    FILE *fp = fopen("D:\WWW\Yazilim\cLionProject\untitled3\Sayilar.txt", "r");

    if (fp == NULL)
    {
        printf("Error: could not open file %s", filename);
        return 1;
    }

    // reading line by line, max 256 bytes
    const unsigned MAX_LENGTH = 256;
    char buffer[MAX_LENGTH];

    while (fgets(buffer, MAX_LENGTH, fp))
        printf("%s\n", buffer);

    // close the file
    fclose(fp);

    char *token;
    char *dizi[] = {"1","2"};
    long int dizi2[] = {1, 2};
    int num1, num2;

    token = strtok(buffer, "#");
    printf("token = %s\n", token);
    //num1 = strtol(token, NULL, 10);
    num1 = atoi(token);
    dizi[0] = token;
    dizi2[0] = strtol(dizi[0], NULL, 10);


    token = strtok(NULL, "#");
    printf("token = %s\n", token);
    //num2 = strtol(token, NULL, 10);
    num2 = atoi(token);
    dizi[1] = token;
    dizi2[1] = strtol(dizi[1], NULL, 10);

    printf("%s, %s\n",dizi[0], dizi[1]);
    printf("%ld, %ld\n",dizi2[0], dizi2[1]);
    printf("%d, %d",num1, num2);


    return 0;
}

我如何将两位数（char* 类型）转换为 int？

我想将值从标记转换为整数值 atoi 和 strtol 产生错误结果

输出是

815102162524#622101830754

token = 815102162524

token = 622101830754

815102162524, 622101830754

2147483647, 2147483647

-941623716, -668427166

Answer 1

int main(void) {
    char buffer[] = "815102162524#622101830754\n";
    long long int num1, num2;
    char *p;
    printf("Long long %u bits\n",sizeof(num1)*8);

    num1 = strtoll(buffer, &p, 10);
    printf("token = %c\n", *p);
    num2 = strtoll(p+1,NULL,10);

    printf("%lld, %lld\n",num1,num2);
}

输出

Long long 64 bits
token = #
815102162524, 622101830754

atoi 和 strtol 产生错误的结果

atoi and strtol produce erroneous results

c

arrays

pointers

atoi

strtol