SQL

Question

我有 2 个查询，一个用于导出总订单，另一个用于获取已交付的订单。列名与顺序和值相同。只有条件在子查询中会有所不同。我想分别获取已交付的订单和价值以及单独的整体订单和价值。之后，我想将交付价值从整体价值中除以百分比值。只有一个table，只是条件不同。我希望从 2021-01 年到现在这个月明智。这是我试过但不起作用的例子。请帮助我。

示例：

Select
a.C_Month,
a.C_Orders/B_Orders as per_orders,
a.C_Value/B_Value as per_Value

from(
select 
to_char(estDate,'yyyymm') as B_Month,
null as area,
count(distinct order_id) as B_Orders,
sum (Value) as B_Value 

from table1
where condition1 is not null
and condition2 is ='1'
and to_char(estDate,'yyyymm')>= '202101' 

group by to_char(estDate,'yyyymm')
order by to_char(estDate,'yyyymm')

union

select
to_char(estDate,'yyyymm') as C_Month,
area,
count(distinct order_id) as C_Orders,
sum (Value) as C_Value 

from table1
where condition1 is not null
and condition2 is ='1'
where condition3 is not null
where condition4 is not null

and to_char(estDate,'yyyymm')>= '202101' 

group by to_char(estDate,'yyyymm')
order by to_char(estDate,'yyyymm')

) as a

group by

a.C_Month,
a.C_Orders/B_Orders as per_orders,
a.C_Value/B_Value as per_Value
;

Answer 1

首先，在您的示例中，您要求的是“JOIN”，但您创建的是“UNION”：

按照您的逻辑，您可能需要一个自连接 on B_Month = C_Month。

查询：

  Select
    a.C_Month,
    a.C_Orders/aa.B_Orders as per_orders,
    a.C_Value/aa.B_Value as per_Value
    
    from(
    (select 
    to_char(estDate,'yyyymm') as B_Month,
    null as area,
    count(distinct order_id) as B_Orders,
    sum (Value) as B_Value 
    
    from table1
    where condition1 is not null
    and condition2 is ='1'
    and to_char(estDate,'yyyymm')>= '202101' ) as aa
    
    INNER JOIN
    
    (select
    to_char(estDate,'yyyymm') as C_Month,
    area,
    count(distinct order_id) as C_Orders,
    sum (Value) as C_Value 
    
    from table2
    where condition1 is not null
    and condition2 is ='1'
    where condition3 is not null
    where condition4 is not null
    
    and to_char(estDate,'yyyymm')>= '202101' ) as a
          
    ON aa.B_Month=a.C_Month

查询将 table1 的每一行与 table2 的每一行进行比较，以找到满足连接谓词的所有行对。

请记住，可以根据您想要的输出将“INNER JOIN”替换为其他谓词（LEFT JOIN、RIGHT JOIN、OUTER JOIN、FULL JOIN）。

SQL - Sub select、联合和使用函数

SQL - Sub select, Union and using functions

union

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