如何尝试：除了：工作而不是无限地进行

Question

所以我有一个二维列表，名为 tour:

tour = [ [3, 2, 1,], 
         [4, 7, 9,], 
         [5, 6, 8,], ]

我想让我的代码检查这个列表，看看国王（国际象棋）是否可以正常通过它。我编写的代码可以适用于 N×N 二维列表。它所做的是从数字 1 开始，检查它周围的所有 9 个空格是否有数字 2，重复该过程直到 N×N。问题是，当数字位于列表的一侧时，代码会给出一个 IndexError，为了克服这个问题，我做了一个 try: except: IndexError 但现在当它到达 i = 6 时，它会继续无限地 [=14] =]

def in_list(number, listname):
    """
    this function detects where a certain number is in a 2d list and returns the index of 
    it
    """
    for i, sublist in enumerate(listname):
        if (number in sublist):
            return [i, sublist.index(number)]
        
    return -1
            

def is_king_tour_3by3(tour):
    """
    this function checks for all 9 areas around this number and if it's an IndexError
    i.e. it's at the end of the list it ignores that case
    """
    start = in_list(1, tour)
    i = 2
    counter = len(tour) * len(tour)
    
    while True:
        counter -= 1
        print(i)
        print(start)
        try:
            if(tour[start[0]][start[1] - 1] == i): #starting from checking the number on the left and going counter-clockwise
                i += 1
                start[1] -= 1
            elif(tour[start[0] + 1][start[1] - 1] == i):    
                i += 1
                start[0] += 1
                start[1] -= 1
            elif(tour[start[0] + 1][start[1]] == i):
                i += 1
                start[0] += 1
            elif(tour[start[0] + 1][start[1] + 1] == i):
                i += 1
                start[0] += 1
                start[1] += 1
            elif(tour[start[0]][start[1] + 1] == i):
                i += 1
                start[1] += 1
            elif(tour[start[0] - 1][start[1] + 1] == i):
                i += 1
                start[0] -= 1
                start[1] += 1
            elif(tour[start[0] - 1][start[1]] == i):
                i += 1
                start[0] -= 1
            elif(tour[start[0] - 1][start[1] - 1] == i):
                i += 1
                start[0] -= 1
                start[1] -= 1
        except IndexError:
            pass
        
        if(i == (len(tour) * len(tour))):
            return True
            break
        elif(counter == 0):
            return False
            break

Answer 1

通过将 start[0] < len(tour)-1 and start[1] > 0 添加到行中，您可以检查您是否不在二维列表之外，而不是使用 try: except:。只要 start is > 0 and < len(tour) (if start[0] or start[1] is -1 or len(tour) it might fail)，此代码将解决它：

def in_list(number, listname):
    """
    this function detects where a certain number is in a 2d list and returns the index of 
    it
    """
    for i, sublist in enumerate(listname):
        if (number in sublist):
            return [i, sublist.index(number)]
    
return -1
        

def is_king_tour_3by3(tour):
    """
    this function checks for all 9 areas around this number and if it's an IndexError
    i.e. it's at the end of the list it ignores that case
    """
    start = in_list(1, tour)
    i = 2
    counter = len(tour) * len(tour)
    
while True:
    counter -= 1
    print(i)
    print(start)
    if(start[1] > 0 and tour[start[0]][start[1] - 1] == i): #starting from checking the number on the left and going counter-clockwise
        i += 1
        start[1] -= 1
    elif(start[0] < len(tour)-1 and start[1] > 0 and tour[start[0] + 1][start[1] - 1] == i):    
        i += 1
        start[0] += 1
        start[1] -= 1
    elif(start[0] < len(tour)-1 and tour[start[0] + 1][start[1]] == i):
            i += 1
            start[0] += 1
    elif(start[0] < len(tour)-1 and start[1] < len(tour)-1 and tour[start[0] + 1][start[1] + 1] == i):
        i += 1
        start[0] += 1
        start[1] += 1
    elif(start[1] < len(tour)-1 and tour[start[0]][start[1] + 1] == i):
        i += 1
        start[1] += 1
    elif(start[0] > 0 and start[1] < len(tour)-1 and tour[start[0] - 1][start[1] + 1] == i):
        i += 1
        start[0] -= 1
        start[1] += 1
    elif(start[0] > 0 and tour[start[0] - 1][start[1]] == i):
        i += 1
        start[0] -= 1
    elif(start[0] > 0 and start[1] > 0 and tour[start[0] - 1][start[1] - 1] == i):
        i += 1
        start[0] -= 1
        start[1] -= 1
    
    if(i == (len(tour) * len(tour))):
        return True
        break
    elif(counter == 0):
        return False
        break

tour = [ [3, 2, 1,], 
         [4, 7, 9,], 
         [5, 6, 8,], ]
is_king_tour_3by3(tour)

如何尝试：除了：工作而不是无限地进行

How to get try: except: working without going on infinitely

python

list

try-except