Python 用于提取电子邮件的正则表达式

Question

我正在尝试使用 python 来提取 sentence that contains the email。

sample_str = "This is a random sentence. This one is also random sentence but it contains an email address ---@---.com"

我看到的所有示例都提取了电子邮件，示例：

import re
lst = re.findall('\S+@\S+', sample_str)

但是无论如何都可以提取sentence that contains the email。在这种情况下

op = "This one is also random sentence but it contains an email address ---@---.com"

Answer 1

可以标明句子的开头，中间不匹配句子的结尾。

但这可能很棘手，并且绝对不是通用的解决方案，因为句子不必以字符 [A-Z] 开头，并且可能以与 . [=15 不同的字符结尾=] ?

作为给定示例的想法，您可以使用：

(?<!\S)[A-Z](?:(?![!?.](?!\S)).)*[^\s@]+@[^\s@]+

说明

(?<!\S) 断言左侧空白边界
[A-Z] 匹配字符 A-Z
(?:(?![!?.](?!\S)).)* 匹配任何字符，除了 ! ? 或 . 紧跟空白边界
[^\s@]+@[^\s@]+ 匹配类似格式的电子邮件

Regex demo | Python demo

例子

import re
 
sample_str = "This is a random sentence. This one is also random sentence but it contains an email address ---@---.com"
lst = re.findall('(?<!\S)[A-Z](?:(?![!?.](?!\S)).)*[^\s@]+@[^\s@]+', sample_str) 
 
print(lst)

输出

['This one is also random sentence but it contains an email address ---@---.com']

Python 用于提取电子邮件的正则表达式

Python Regex to extract email

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