strptime 时间转换字符串

Question

我尝试将这样的字符串时间 1:34.21 转换为时间。我使用此 datetime.strptime('1:34.21', '%-H:%M.%S').time() 进行转换，但出现此错误：

Traceback (most recent call last):
File "<stdin>", line 1, in <module>
  File "/Library/Frameworks/Python.framework/Versions/3.9/lib/python3.9/_strptime.py", line 568, in _strptime_datetime
    tt, fraction, gmtoff_fraction = _strptime(data_string, format)
  File "/Library/Frameworks/Python.framework/Versions/3.9/lib/python3.9/_strptime.py", line 341, in _strptime
    raise ValueError("'%s' is a bad directive in format '%s'" %
ValueError: '-' is a bad directive in format '%-H:%M.%S'

Answer 1

只要把'%-H:%M.%S'改成'%H:%M.%S'

from datetime import datetime
s = '1:34.21'
print(datetime.strptime(s, '%H:%M.%S').time())

输出：

01:34:21

strptime 时间转换字符串

strptime convert string time to time

python

python-3.x

datetime

strptime