如何编写 RSpec 测试来将字符串与其预期的子字符串进行比较？

Question

我有一个这样的 RSpec 测试：

context 'test #EnvironmentFile= method' do

  it 'compares the command generated with the expected command' do

    knife = EnvironmentFromFile.new(@knife_cfg_file)

    knife.environment_file=(@environment_file)

    expect(knife.chef_cmd_to_s).to eql("C:/blah/blah/bin/knife environment from file MySampleEnvironment.json --config 'knife.rb'")

  end
end

现在，为了避免平台依赖性，eql() 中的预期消息应该是没有初始 C:/blah/blah/bin/ 部分的子字符串。

我预期的消息应该是 "knife environment from file MySampleEnvironment.json --config 'knife.rb'"

这应该与从 knife.chef_cmd_to_s 方法返回的实际消息相匹配： "C:/blah/blah/bin/knife environment from file MySampleEnvironment.json --config 'knife.rb'"

我该怎么做？什么 Rspec 匹配器用于此？

Answer 1

这是您要使用 include 匹配器 (documentation) 的地方。

context 'test #EnvironmentFile= method' do

  it 'compares the command generated with the expected command' do

    knife = EnvironmentFromFile.new(@knife_cfg_file)

    knife.environment_file=(@environment_file)

    expect(knife.chef_cmd_to_s).to include("knife environment from file MySampleEnvironment.json --config 'knife.rb'")

  end
end

如何编写 RSpec 测试来将字符串与其预期的子字符串进行比较？

How to write a RSpec test to compare a string with its expected substring?

ruby

rspec

rspec2