Django 3.2.3 我正在尝试使用其字段和属性方法序列化对象

Django 3.2.3 I'm trying to serialize object with its fields and properties methods

我是 django 框架的新手,我只是想 return 一个模型对象及其属性返回到 ajax 调用作为 Json 响应。我有一个带有 属性 余额的项目模型,其中 return 是一个整数值。这是我的代码:

models.py

class Item(models.Model):
   entered_by = models.ForeignKey(User, on_delete=models.PROTECT)
   name = models.CharField(max_length=50, blank=True)

   @property
   def balance(self):
      return Stock.objects.filter(item_id=self.id).aggregate(Sum('quantity')).get('quantity__sum')

class Stock(models.Model):
   item = models.ForeignKey(Item, on_delete=models.PROTECT)
   name = models.CharField(max_length=50, blank=True)
   quantity = models.PositiveIntegerField()
      

serializers.py

from rest_framework import serializers
from .models import Item

class ItemSerializer(serializers.ModelSerializer):
   balance = serializers.SerializerMethodField(source="get_balance")

   class Meta:
      model = Item
      fields = ('entered_by', 'name', 'balance')

views.py

from stocks.serializers import *
from django.http import HttpResponse, JsonResponse

def viewItem(request):
   if request.is_ajax and request.method == "GET":
      id = request.GET.get("item_id", None)
      item = Item.objects.get(id=id)
      if item:
         serializer = ItemSerializer()
         # return serializer.data
         return JsonResponse(serializer.data, status = 200)

我正在寻找的输出是这样的 Json 输出:

{
 name:"item name",
 entered_by: null,
 balance: 10,
}

现在这就是我得到的

{
entered_by: null
name: ""
}

任何想法都会受到赞赏。

你必须在序列化器中传递对象,所以:

serializer = ItemSerializer(item)
return JsonResponse(serializer.data, status=200)

或shorthand:

return JsonResponse(ItemSerializer(item).data, status=200)

编辑:

对于序列化程序中的问题,是因为 source。尝试将其更改为:

class ItemSerializer(serializers.ModelSerializer):
   balance = serializers.SerializerMethodField()

   class Meta:
      model = Item
      fields = ('entered_by', 'name', 'balance')

   def get_balance(self, obj)
      return obj.balance