如何在无痛脚本中深度克隆对象字段

Question

我想在更新对象字段时创建一个新字段来存储旧值。

原文档为：

 {
        "_index" : "test",
        "_id" : "15895_-1",
        "_source" : {
            "device" : {
                  "standard": {
                       "name" : "unknown",
                       "brand" : "unknown"
                  },
                  "other": "other"
             }
        }
}

这是我的 updateByquery 代码：

GET test/_update_by_query
{
  "script": {
    "source": """
    if (params.deviceStandard != null) {
      ctx._source['device_algoed'] = ctx._source['device'];
      
      ctx._source['device']['standard']['series'] = params.deviceStandard.series;
      ctx._source['device']['standard']['brand'] = params.deviceStandard.brand;
    }
    """,
    "params": {
      "deviceStandard": {
        "series" : "unknown",
        "brand" : "OPPO"
      }
    }
  },
  "query": {
    "bool": {
      "filter": {
        "term": {
          "_id": "15895_-1"
        }
      }
    }
  }
}

当我更改 ctx._source['device']['standard'] 时，ctx._source['device_algoed'] 也会更改。那么如何将 ctx._source['device']['standard'] 深度克隆到 ctx._source['device_algoed']?

Answer 1

你可以做的是从原始地图创建一个新地图：

  ctx._source['device_algoed'] = [:];
  ctx._source['device_algoed'].putAll(ctx._source['device']);

然后可以自由修改ctx._source['device']而不影响ctx._source['device_algoed']

就是这样！

如何在无痛脚本中深度克隆对象字段

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