如果使用 python 请求响应为 404，我该如何跳过？

Question

for user in comments['comment_id']:
  try:
    get_profile(user)
  except urllib.error.HTTPError:
    continue

我遇到过这样的错误，我不知道如何解决这个问题

<ipython-input-38-c9a67ae2e3f1> in <module>()
      2 for user in comments['comment_id']:
      3   try:
----> 4     get_profile(user)
      5   except urllib.error.HTTPError:
      6     continue

/usr/local/lib/python3.7/dist-packages/requests/models.py in raise_for_status(self)
    939 
    940         if http_error_msg:
--> 941             raise HTTPError(http_error_msg, response=self)
    942 
    943     def close(self):

HTTPError: 404 Client Error: Not Found for url: https://m.facebook.com/344608967148594/about/

Answer 1

for user in comments['comment_id']:
  try:
    get_profile(user)
  except:
    continue

如果使用 python 请求响应为 404，我该如何跳过？

How do I skip if the response is 404 using python requests?

python

http-status-code-404

python-requests