如何获取 Substrate 中的当前区块号？

Question

我的问题是：

如何获取当前区块号？
如何将当前块号转换为 u32？

我正在尝试在模板托盘中编写一个函数，该函数采用 u32（输入参数）并将该数字添加到当前块编号。

#[pallet::weight(10_000 + T::DbWeight::get().writes(1))]
    pub fn revoke(origin: OriginFor<T>, number: u32) -> DispatchResult {
        let caller = ensure_signed(origin)?;

        // GET CURRENT BLOCK NUMBER
        // CONVERT CURRENT BLOCK NUMBER TYPE TO U32
        // TARGET_BLOCK = CURRENT_BLOCK_NUMBER + NUMBER
        // STORE TARGET_BLOCK

        Ok(())
    }

我已阅读以下文档（以及更多），但我无法使代码正常工作。

这是我的尝试列表：

let y = System::block_number() as u32;
let z = sp_std::alloc::System::block_num() as u32;
let p = Self::block_number();
let h = BlockNumberProvider::current_block_number();
let h: BlockNumberFor<T> = BlockNumberProvider::current_block_number();
let p = BlockNumberProvider::current_block_number() as u32;
target_block = target_block + p;
let x = <T as sp_runtime::offchain::storage_lock::BlockNumberProvider>::current_block_number();
let x = <T as BlockNumberProvider>::current_block_number();
let j = frame_system::Pallet<Config>::block_number();
target_block = target_block + h;
let y = Self::BlockNumber;
let yy = <T as frame_system::Config>::BlockNumber;
let xc = frame_system::block_number();
let current_block = System::block_number()
.saturated_into::<u64>()
.saturating_sub(1);
let u = Number::<T>::get(T::BlockNumber);
let w = T::BlockNumber::block_number();
let n = <T as frame_system::Config>::BlockNumber::block_number();
let m = frame_system::<T>::BlockNumber;
let un = BlockNumberFor;
let current_block_number: u32 = <frame_system::Pallet<T>>::block_number();
let now_block_number = <frame_system::Module<T>>::block_number();
let now_block_number = <frame_system::Pallet<T>>::block_number();
let now_block_number_b: <T as frame_system::Config>::BlockNumber = <frame_system::Pallet<T>>::block_number();
T::BlockNumber;
let xp = now_block_number_b + 10;
let h: BlockNumberFor<T> = BlockNumberProvider::current_block_number();
let x: <T as Config>::BlockNumber = BlockNumberProvider::current_block_number();
let x = frame_system::Config::block_number();
let c = block_number();
let v = <T as frame_system::Config>::BlockNumber;
let x = block;
let q = block.into();
let x: Number<T> = block.into();
let f: u32 = x.into();
let v = 10.into();
let w: BlockNumber_<T> = block.into();
let target_block = target_block + f;
let current_block_number: Number<T> = <frame_system::Pallet<T>>::block_number();
let h: BlockNumberFor<T> = BlockNumberProvider::current_block_number();
let x: BlockNumber_<T> = frame_system::pallet::Pallet::current_block_number();
let y: BlockNumberFor<T> = frame_system::pallet::Pallet::current_block_number();
let z: T::BlockNumber = frame_system::pallet::Pallet::current_block_number();

如果您能提供任何帮助，我将不胜感激。

Answer 1

这是工作代码：

#[pallet::weight(10_000 + T::DbWeight::get().writes(1))]
    pub fn set_block_delay(origin: OriginFor<T>, block: T::BlockNumber) -> DispatchResult {
        let caller = ensure_signed(origin)?;
        
        let current_block_number = <frame_system::Pallet<T>>::block_number();

        let block_delay: u32 = 10;

        let target_block = current_block_number + block_delay.into();

        ensure!(target_block < block, "fail");

        Ok(())
    }

如何获取 Substrate 中的当前区块号？

How do you get the current block number in Substrate?

rust

blockchain

substrate