R - 模糊查找和重新编码

Question

我正在清理 10 多个学区提交的人口统计数据，但提交的不是 standardized/uniform。我想找到模式并重新编码，以便数据干净简单。

假设我有一个名为 Race 的变量，其中一个类别是 Native Hawaiian - Pacific Islander。

学校 A 提交此类别为 Native Hawaiian or Other Pacific Islander。学校 B 提交此类别为 Native Hawaiian/Pacific Islander。学校 C 将此类别提交为 Native Hawaiian or Pacific Islander.

我如何重新编码，如果 R 在变量中的任何地方看到单词 Pacific，它将重新编码为 Native Hawaiian - Pacific Islander？

这里是原始数据：

df_original <- data.frame(Race=c("Native Hawaiian or Other Pacific Islander",
                                 "Native Hawaiian/Pacific Islander", "Native Hawaiian or Pacific Islander",
                                 "Black or African American", "Black", "Black/African American"))

这是理想的清理数据：

df_desired <- data.frame(Race=c("Native Hawaiian - Pacific Islander","Native Hawaiian - Pacific Islander",
                                "Native Hawaiian - Pacific Islander","Black - African American",
                                "Black - African American","Black - African American"))

Answer 1

对于包含“Pacific”的字符串，

grepl() 将 return TRUE，否则 False。使用它来对您的矢量进行子集化并替换为您想要的字符串：

df_original$Race[grepl("Pacific", df_original$Race)] <- "Native Hawaiian - Pacific Islander"

Answer 2

将 str_detect 与 case_when

结合使用

library(dplyr)
library(stringr)
df_original %>% 
    mutate(Race2 = case_when(str_detect(Race, '\bPacific\b') ~
      "Native Hawaiian - Pacific Islander", 
            TRUE ~ "Black - African American"))

-输出

                                Race                              Race2
1 Native Hawaiian or Other Pacific Islander Native Hawaiian - Pacific Islander
2          Native Hawaiian/Pacific Islander Native Hawaiian - Pacific Islander
3       Native Hawaiian or Pacific Islander Native Hawaiian - Pacific Islander
4                 Black or African American           Black - African American
5                                     Black           Black - African American
6                    Black/African American           Black - African American

另一种选择是创建一个 key/value 数据集，其中包含要替换的模式及其相应的值，然后使用原始数据 [=17] 执行 regex_left_join（来自 fuzzyjoin） =]

library(fuzzyjoin)
keydat <- tibble(Race = c("Pacific", "Black"), 
   Race2 = c("Native Hawaiian - Pacific Islander", "Black - African American"))
regex_left_join(df_original, keydat) %>%
        transmute(Race = Race2)
#Joining by: "Race"
#                                Race
#1 Native Hawaiian - Pacific Islander
#2 Native Hawaiian - Pacific Islander
#3 Native Hawaiian - Pacific Islander
#4           Black - African American
#5           Black - African American
#6           Black - African American

R - 模糊查找和重新编码

R - Fuzzy find and recode

r

string

data-cleaning

recode

fuzzy-comparison