打字稿错误 TS(2304) jest.MockedFunction - jest.MockedFunction 的正确用法是什么？

Question

任何人都可以帮助解决我在下面列出的以下代码中收到的 Typescript 错误。

引发错误的代码行是const mockedFunction = createRepo as jest.MockedFunction<typeof create_publish_repository>;

我正在努力学习如何使用 jest.MockedFunction。我在 VSCode 中收到的错误是：

找不到名称 createRepo。 ts(2304) 任何

import { PublishRepository, create_publish_repository } from "../../../../repository";
jest.mock("../../../../repository");

describe("/api/publish/[id]", () => {
  test("returns a post with published state set to true", async () => {
      // this raises an error
      const mockedFunction = createRepo as jest.MockedFunction<typeof create_publish_repository>;
  }

存储库 ./publish.repo

import { Post } from "@prisma/client"
import { Context } from "../context"


export class PublishRepository {
    private context: Context

    constructor(context: Context) {
        this.context = context
    }

    async set_published(post_id: string | string[]): Promise<Post> {
        return await this.context.prisma.post.update({
            where: { id: Number(post_id) },
            data: { published: true },
        });
    }
}


export const create_publish_repository = (context: Context): PublishRepository => {
    return new PublishRepository(context)
}

存储库模块 ./index.ts

export { create_publish_repository, PublishRepository } from "./publish.repo";

Answer 1

解决了...我需要重命名我的模拟函数变量以匹配用于模拟的导入函数的名称。

由于没有导入名为 createRepo 的函数，打字稿会引发错误。

没有调用 createRepo 的导入，引发错误

import { PublishRepository, create_publish_repository } from "../../../../repository";

const mockedFunction = createRepo as jest.MockedFunction<typeof create_publish_repository>;

更正了模拟函数名称 create_publish_repository 以匹配导入

import { PublishRepository, create_publish_repository } from "../../../../repository";

const mockedFunction = create_publish_repository as jest.MockedFunction<typeof create_publish_repository>;

打字稿错误 TS(2304) jest.MockedFunction - jest.MockedFunction 的正确用法是什么？

Typescript Error TS(2304) jest.MockedFunction - What Is The Correct Usage For jest.MockedFunction?

typescript

jestjs

ts-jest