MySQL：将具有 StackOverflow 样式编码 URL 的字段转换为 HTML

Question

我们有一个遗留数据库 table 充满了类似 Whosebug 的编码 URLs。

=====================================================================================
| TABLE_COMMENTS                                                                    |
=====================================================================================
| f_ID | f_comment                                                                 |
-------------------------------------------------------------------------------------
|   1  | To buy coffee [click here](https://google.com) or [here](https://bing.com) |
|   2  | Check [this out](https://whosebug.com)                                |
|   3  | [Cat Photos](https://google.com/images/?cats)                              |
=====================================================================================

我需要 SELECT 这些作为标准 HTML 所以它们看起来像下面 table.

| f_comment                                                                                        |
----------------------------------------------------------------------------------------------------
| To buy coffee <a href="https://google.com">click here</a> or <a href="https://bing.com">here</a> |
| Check <a href="https://whosebug.com">this out</a>                                           |
| <a href="https://google.com/images/?cats">Cat Photos</a>                                         |
====================================================================================================

如果 f_comment 字段中只有一个 URL，我有一种方法可以使用，但我不知道如何让它工作，比如 row 1 其中有两个 URLs.

SELECT 
    CONCAT(
        substring_index(substring_index(f_comment, '[', 1),')', 1),
        "<a href=", 
        substring_index(substring_index(f_comment, '(', -1),')', 1),
        ">",
        substring_index(substring_index(f_comment, '[', -1),']', 1),
        "</a>"
    )
    AS f_replacementtext
FROM TABLE_COMMENTS;

SQL Fiddle

我的 不完整 查询的结果，它错过了 f_ID 1

的第一个 URL

 ==========================================================
| f_comment                                                |
 ----------------------------------------------------------
| To buy coffee <a href="https://bing.com">here</a>        |
| Check <a href="https://whosebug.com">this out</a>   |
| <a href="https://google.com/images/?cats">Cat Photos</a> |
 ==========================================================

Answer 1

set @col =
'To buy coffee <a src=https://google.com>click here</a> or <a src=https://bing.com>here</a>';
Query OK, 0 rows affected (0.00 sec)

mysql> SELECT REGEXP_REPLACE( @col, '<a src=(http.*?)>(.*?)</a>', '[]()');
+----------------------------------------------------------------------------+
| REGEXP_REPLACE( @col, '<a src=(http.*?)>(.*?)</a>', '[]()')            |
+----------------------------------------------------------------------------+
| To buy coffee [click here](https://google.com) or [here](https://bing.com) |
+----------------------------------------------------------------------------+

走另一条路...

SET @col =
'To buy coffee [click here](https://google.com) or [here](https://bing.com)';
SELECT
REGEXP_REPLACE( @col, '\[(.*?)\][(](http.*?)[)]',
                      '<a src=$2>$1</a>' ); 

+------------------------------------------------------------------------------------------------------+
| REGEXP_REPLACE( @col, '\[(.*?)\][(](http.*?)[)]',
                          '<a src=$2>$1</a>' ) |
+------------------------------------------------------------------------------------------------------+
| To buy coffee <a src=https://google.com>click here</a> or <a src=https://bing.com>here</a>           |
+------------------------------------------------------------------------------------------------------+
1 row in set (0.00 sec)

MySQL：将具有 StackOverflow 样式编码 URL 的字段转换为 HTML

MySQL: Convert Field with StackOverflow-style Coded URLs to HTML

regex

mysql

regexp-replace