UITextView shouldInteractWith 委托在警报完成时返回值

Question

我在可以包含 URL 的 table 视图单元格中有一个文本视图。当用户点击 URL 时，我想发出警报以确保用户在处理 URL 之前想要继续。我试图在适当的委托方法中实现它，但我被卡住了，因为 return 值不能在警报的完成块中。在使用此方法 return 之前如何等待用户做出选择？

相关代码：

func textView(_ textView: UITextView, shouldInteractWith URL: URL, in characterRange: NSRange, interaction: UITextItemInteraction) -> Bool {
        var alert = UIAlertController(title: "Are you sure?", message: "You are about to leave the app to open an external link", preferredStyle: .alert)
        let yesAction = UIAlertAction(title: "Yes", style: .default) { _ in
            alert.dismiss(animated: true) {
                // return true would go here
            }
        }
        let cancelAction = UIAlertAction(title: "Cancel", style: .cancel) { _ in
            alert.dismiss(animated: true) {
                // return false would go here
            }
        }
        alert.addAction(cancelAction)
        alert.addAction(yesAction)
        UIApplication.shared.firstKeyWindow?.rootViewController?.present(alert, animated: true, completion: nil)
        // Traditionally the return should go here
    }

Answer 1

让代表等待响应是不好的做法。我的解决方案是

alert.dismiss(animated: true) {
    UIApplication.shared.open(url)
}

并向委托人返回 false。这样我就把 URL 处理留给我的代码而不是 iOS 本机行为

UITextView shouldInteractWith 委托在警报完成时返回值

UITextView shouldInteractWith delegate returning value in alert completion

uitextview

uitextviewdelegate

ios

swift