引发异常后打印行

Question

有没有办法在引发异常后打印出字典的内容？

假设字典是这样的，

d = {"orange":[1,2], "yellow":[5], "red":[2,6,7]}

我希望它看起来像这样：

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-63-719ba08e2a6c> in <module>
----> 1 raise TypeError("This is a TypeError. Printing out contents of dictionary...")

TypeError: This is a TypeError.
orange
1
2

yellow
5

red
2
6
7

这可能吗？

Answer 1

将字典附加到异常消息中。

raise TypeError("This is a TypeError. Printing out contents of dictionary...\n" + str(d))

Answer 2

格式不对，但可以解决问题。

d = {"orange":[1,2], "yellow":[5], "red":[2,6,7]}

try:
    d["melon"]
except:
    raise Exception(f"{str(d)}")

或者你可以这样做：

try:
    d["melon"]
except:
    for k in d.keys():
        print(k, d[k])

Answer 3

try:
    # code here
except Exception as e:
    # Try and replace `Exception` with the error you're getting
    print(f"Error = {e}")
    for name, val in zip(d.keys(), d.values()):
        print(name)
        for i in val:
            print(i)

请注意 except Exception:，try 循环将排除 any 错误

引发异常后打印行

Print lines after raising exception

python

error-handling

dictionary

raise