无法在配置单元中分解 json 字符串

Question

[{"name":"john","id":12,"location":"delhi"},{"name":"raj","id":18,"location":"mumbai"},{"name":"Rahul","id":14,"location":"hyd"}]

在配置单元 table 中的一条记录上使用 get_json_object 后，我得到了这个字符串（不是结构）。我需要分解它以创建一个新的 table，其列名称为名称、ID 和位置。有人可以帮忙吗

Explode() 或 inline() 接受结构数组。已尝试 explode(Array(struct(my get_json_object output))) 但没有给出预期的结果。

Answer 1

首先将字符串转换为 JSON 个对象的数组：删除方括号，在大括号之间用逗号分隔并展开。然后使用 json_tuple 和横向视图来提取所有值。请参阅此演示：

with mytable as (--demo table, use your table instead
select '[{"name":"john","id":12,"location":"delhi"},{"name":"raj","id":18,"location":"mumbai"},{"name":"Rahul","id":14,"location":"hyd"}]' as json_string
)

select --t.json_string as original_string, --commented
      e.pos as position_in_array,
      --values from json
      x.name, x.id, x.location
      
  from mytable t 
      lateral view outer posexplode( split(regexp_replace(json_string,'^\[|\]$',''),      --remove []
                          '(?<=\}),(?=\{)'  --split by comma only after } and before {
                         )                    --converted to array of json strings
                               )e as pos, json --exploded array element with position
       --extract all from e.json 
      lateral view json_tuple(e.json,'name', 'id', 'location') x as name, id, location

结果：

position_in_array  x.name   x.id    x.location  
0                  john     12      delhi
1                  raj      18      mumbai
2                  Rahul    14      hyd

无法在配置单元中分解 json 字符串

Not able to explode json string in hive

sql

arrays

json

hive

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