根据给定的服务列表查找目标 windows 主机中的哪些服务 运行，如果服务不是 运行 则启动

Question

我有一组 windows 服务，需要查明这些服务是否在目标 windows 主机中 运行。如果至少有一项服务没有 运行 我需要启动这些服务并且需要将启动模式设置为自动。

- name: Check weather service is running or not
    ansible.windows.win_service_info:
      name: "{{ item }}"
    register: win_service_info
    with_items:
      - BrokerInfrastructure #Background Tasks Infrastructure (BrokerInfrastructure) Service
      - DcomLaunch #DCOM Server Process Launcher Service
      - gpsvc #Group Policy Client Service
      
  - name: Start the services
    ansible.windows.win_service:
      name: << don't know how to write this part >>
      start_mode: auto
      state: started
    register: service_startup 
    with_items: "{{ win_service_info.results }}"
    when: << don't know how to write this part >>

Answer 1

您不需要事先找到服务状态。只需描述服务应该处于的状态，ansible 将报告 changed 如果它必须修改任何东西（启动服务，更改启动模式...）或 ok 如果它已经在预期状态。

  - name: Start/modify the services if needed
    ansible.windows.win_service:
      name: "{{ item }}"
      start_mode: auto
      state: started
    with_items:
      - BrokerInfrastructure 
      - DcomLaunch
      - gpsvc

---

现在，如果您仍想在执行特定任务之前检测服务状态，您应该简单地调试 win_service_info.results 变量以获得一个很好的概览。我无法自己测试，因为我手边没有 windows 盒子。但是如果我相信win_service_info module's returned values documentation，你可以这样做：

- name: do something depending on service state
  debug:
    msg: "I would do something because service {{ item.services.0.name }}
           is in state {{ item.services.0.state }}"
  when:
    - item.exists
    - item.services.0.state in ['stopped', 'paused']
  loop: "{{ win_service_info }}"