如何在 Groovy 的反斜杠中嵌入值时更新 JSON 负载

Question

在 Groovy 中，我必须更新 JSON 负载中的值并进行 API 调用。我运行在更新有效负载时面临挑战，因为字段嵌入反斜杠中。是否有更简单的方法直接更新以下有效负载中的服务器，即更新 1. JSON 有效载荷 到 2。已更新 JSON 有效载荷（更新名称和主机值）。

1. JSON 负载：

    {
    "environment": "dev",
    "config": "Create",
    "configType": "Server",
    "ServerName": "",
    "Servers": "[\{\"name\":\"Server-test_1\",\"host\":\"test.com\",\"port\":\"443\",\"tls\":\"2-way\"}]",
    "tsHost": "",
    "tsPort": "",
    "tsSSLOption": "1-way"
    }

2。已更新 JSON 负载：

    {
    "environment": "dev",
    "config": "Update",
    "configType": "Server",
    "ServerName": "",
    "Servers": "[\{\"name\":\"Server-test_2\",\"host\":\"test123.com\",\"port\":\"443\",\"tls\":\"2-way\"}]",
    "tsHost": "",
    "tsPort": "",
    "tsSSLOption": "1-way"
    }

尝试了以下（在转换过程中丢失反斜杠）：

代码：

    def json = $/ {
    "environment": "dev",
    "config": "Create",
    "configType": "Server",
    "ServerName": "",
    "Servers": "[\{\"name\":\"Server-test_1\",\"host\":\"test.com\",\"port\":\"443\",\"tls\":\"2-way\"}]",
    "tsHost": "",
    "tsPort": "",
    "tsSSLOption": "1-way"
    } 
/$
    def parser = new JsonSlurper()
    def jsonResp = parser.parseText(json)
    println(jsonResp.Servers)
    jsonResp.Servers.name = "Server-test_2"
    jsonResp.Servers.host = "test123.com"

Answer 1

Servers 是你初始 json 中的一个字符串 - 你必须解析它

import groovy.json.*

def json = $/ {
    "environment": "dev",
    "config": "Create",
    "configType": "Server",
    "ServerName": "",
    "Servers": "[{\"name\":\"Server-test_1\",\"host\":\"test.com\",\"port\":\"443\",\"tls\":\"2-way\"}]",
    "tsHost": "",
    "tsPort": "",
    "tsSSLOption": "1-way"
    } 
/$
def parser = new JsonSlurper()
def jsonResp = parser.parseText(json)
println(jsonResp.Servers)

def servers = parser.parseText(jsonResp.Servers)
servers[0].name="Server-test_2"
servers[0].host="test123.com"
jsonResp.Servers = JsonOutput.toJson(servers)
json = JsonOutput.prettyPrint(JsonOutput.toJson(jsonResp))

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