如何根据自定义键 python 弹出列表的最大值

Question

我有一个字符串列表：["abc", "a", "abcdef", "g", "h"]。我正在尝试根据自定义键弹出列表的最大值。在这种情况下，我的自定义键是列表中项目的长度： Input: ["abc", "a", "abcdef", "g", "h"] Output: "abcdef", 6 其中自定义键是 len。此外，该列表将没有最大项目：["abc", "a", "g", "h"]。有什么办法吗？

Answer 1

>>> strings = ["abc", "a", "abcdef", "g", "h"]
>>> strings.remove(max(strings, key=len))
>>> strings
['abc', 'a', 'g', 'h']
>>> def pop_max(iterable, key=lambda x: x):
...     m = max(iterable, key=key)
...     iterable.remove(m)
...     return m, key(m)
...
>>> pop_max(["abc", "a", "abcdef", "g", "h"])
('h', 'h')
>>> pop_max(["abc", "a", "abcdef", "g", "h"], key=len)
('abcdef', 6)

如何根据自定义键 python 弹出列表的最大值

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