Javascript- 比较排除某些键的 2 个对象

Question

我在玩笑测试中根据给定的值创建了 2 个对象，并希望它们相等，除了为每个对象单独生成的属性 uuid。

uuid可以多次深度嵌套。例如：

const object1 = { uuid: '5435443', name: 'xxx', branches: [{ uuid: '643643', children: [{ uuid: '65654' /* and so on */ }] }];
const object2 = { uuid: '7657657', name: 'xxx', branches: [{ uuid: '443444', children: [{ uuid: '09809' }] }];

如何比较对象，忽略 uuid 属性？

Answer 1

您可以使用 expect.any 忽略 uuid 属性。只需确保属性存在，并且 uuid 是一个字符串：

describe("Compare 2 objects", () => {
  it("should ...", () => {
    const actual = { uuid: '5435443', name: 'xxx', branches: [{ uuid: '643643', children: [{ uuid: '65654' }] }] };

    const expected = {
      uuid: expect.any(String), // <--
      name: 'xxx',
      branches: [{ uuid: expect.any(String), children: [{ uuid: expect.any(String) }] }]
    };

    expect(actual).toEqual(expected);
  });
});

Answer 2

我通过以下解决方案成功实现了这一目标：

const object1 = { uuid: '5435443', name: 'xxx', branches: [{ uuid: '643643', children: [{ uuid: '65654' /* and so on */ }] }] };
const object2 = { uuid: '7657657', name: 'xxx', branches: [{ uuid: '443444', children: [{ uuid: '09809' }] }] };

const compareExcludeKeys = (object1, object2, excludeKeys = []) => {
  if (Object.keys(object1).length !== Object.keys(object2).length) return false;
  return Object.entries(object1).reduce((isEqual, [key, value]) => {
    const isValueEqual = typeof value === 'object' && value !== null
      ? compareExcludeKeys(value, object2[key], excludeKeys) 
      : excludeKeys.includes(key) || object2[key] === value;
    return isEqual && isValueEqual;
  }, true);
};

console.log(compareExcludeKeys(object1, object2, ['uuid']));

Answer 3

你可以先去掉uuid再比较。

const object1 = { uuid: '5435443', name: 'xxx', branches: [{ uuid: '643643', children: [{ uuid: '65654' /* and so on */ }] }]};
const object2 = { uuid: '7657657', name: 'xxx', branches: [{ uuid: '443444', children: [{ uuid: '09809' }] }]};

const removeUuid = o => {
  if (o) {
    switch (typeof o) {
    case "object":
      delete o.uuid;
      Object.keys(o).forEach(k => removeUuid(o[k]));
      break;
    case "array":
      o.forEach(a => removeUuid(a));
    }
  }
}

removeUuid(object1);
removeUuid(object2);

expect(object1).toBe(object2);

Javascript- 比较排除某些键的 2 个对象

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