如何在C ++中读取由两个单词限制的.txt文件中的内容

Question

我是 C++ 新手，我有一个包含以下行的文件：

 ~~ 13!-!43??
CaKnX5H83G
 ~~ 107!-!22??
 ~~ 140!-!274??
 ~~ 233!-!75??
begin
 ~~ 143!-!208??
143
 ~~ 246!-!138??
 ~~ 79!-!141??
vC5FxcKEiN
 ~~ 60!-!201??
83
end
 ~~ 234!-!253??
 ~~ 51!-!236??

我要读取两个词（begin,end）之间的内容，去掉所有其他分隔符~~!-! ??

我试过这段代码：

#include <iostream>
#include <fstream>
using namespace std;
int main() {
    ifstream my_file;
    my_file.open("file.txt", ios::in);

    if (!my_file) {
        cout << "No such file";
    }
    else {
        string ch;
        string qlline;
        while (1) {
            getline(my_file, qlline);
            if (my_file.eof()) {break;}
            if (qlline.find("end") == 0) {break;}
            if (qlline.find("begin") != 0) {continue;}
            my_file >> ch;
            cout << ch;

        }

结果很奇怪，完全不是我想要的！ P.S: 不知道如何不考虑分隔符(~~!-!??)！

任何建议，修改，或link请！提前致谢。

Answer 1

#include <iostream>
#include <fstream>

int main()
{
    std::ifstream my_file("file.txt");

    if (!my_file) {
        std::cout << "No such file";
        exit(1);
    }

    std::string qlline;
    bool insideSection = false;
    while (getline(my_file, qlline))
    {
        // I have correctly read a line from the file.
        // Now check for boundary markers.

        if (qlline.find("end") == 0)   {insideSection = false;break;}
        if (qlline.find("begin") == 0) {insideSection = true; continue;}

        // Are we inside the section of the file I want.
        if (!insideSection) {
            continue;
        }

        // I am now inside the part of the file with
        // text I want.
        std::cout << qlline << "\n";
    }
}

如何在C ++中读取由两个单词限制的.txt文件中的内容

how to read content in a .txt file that is limited by two words in C ++

c++

codeblocks

fstream

sqlline