从 GetAsync 异常访问 HttpRequestMessage
Access HttpRequestMessage from GetAsync exception
如何从 GetAsync
异常中获取 HttpRequestMessage
:
try {
using var responseMsg = await httpClient.GetAsync(requestUri);
var requestMessage = responseMsg.RequestMessage;
} catch (Exception ex) {
var requestMessage = ????
Log(requestMessage.Headers);
}
您可以在尝试前手动创建HttpRequestMessage
,然后使用HttpClient发送:
HttpRequestMessage httpRequest = new HttpRequestMessage
{
Method = HttpMethod.Get,
RequestUri = uri
};
try
{
HttpClient client = new HttpClient();
var response = await client.SendAsync(httpRequest);
}
catch(Exception ex)
{
var x = httpRequest.Headers;
}
在try<->catch之外创建的对象,可以在每个部分使用。
如何从 GetAsync
异常中获取 HttpRequestMessage
:
try {
using var responseMsg = await httpClient.GetAsync(requestUri);
var requestMessage = responseMsg.RequestMessage;
} catch (Exception ex) {
var requestMessage = ????
Log(requestMessage.Headers);
}
您可以在尝试前手动创建HttpRequestMessage
,然后使用HttpClient发送:
HttpRequestMessage httpRequest = new HttpRequestMessage
{
Method = HttpMethod.Get,
RequestUri = uri
};
try
{
HttpClient client = new HttpClient();
var response = await client.SendAsync(httpRequest);
}
catch(Exception ex)
{
var x = httpRequest.Headers;
}
在try<->catch之外创建的对象,可以在每个部分使用。