如何将未标记的数组排列成标记的数组？

Question

我正在为印度股票市场制作交易机器人。我有这种形式的库存数据

data = [[ 1627875900, 434.75, 435.8, 432.55, 434.9, 1750806 ], [ 1627876800, 434.75, 435.2, 432.7, 433, 905388 ], [ 1627877700, 432.9, 433.75, 431.8, 433.55, 689338 ],...........]

按顺序表示为

[[time stamp, Open Price, High Price, Low Price, Close Price, Volume], [.....]]

我想将其排列在带标签的数组中

{ open: [...], close: [...], high: [...], low: [...], volume: [...] }

我正在使用 TALIB 库，它使用这种形式的数据来使用指标。

我已经看到使用 Python 和 pandas 可以完成此操作，但需要 javascript.

中的解决方案

谢谢

Answer 1

这是一个数据操作的例子。

const data = [[ 1627875900, 434.75, 435.8, 432.55, 434.9, 1750806 ], [ 1627876800, 434.75, 435.2, 432.7, 433, 905388 ], [ 1627877700, 432.9, 433.75, 431.8, 433.55, 689338 ]];
const open = [], close = [], high = [], low = [], volume = [];

data.forEach(elm => {
    open.push(elm[1])
    high.push(elm[2])
    low.push(elm[3])
    close.push(elm[4])
    volume.push(elm[5])
});

const result = {open, high, low, close, volume};

console.log(result);

Answer 2

试试这个：

const data = [
  [1627875900, 434.75, 435.8, 432.55, 434.9, 1750806],
  [1627876800, 434.75, 435.2, 432.7, 433, 905388],
  [1627877700, 432.9, 433.75, 431.8, 433.55, 689338]
]
const result = {
  open: [],
  high: [],
  low: [],
  close: [],
  volume: []
}
data.forEach(item => {
  result.open.push(item[1])
  result.high.push(item[2])
  result.low.push(item[3])
  result.close.push(item[4])
  result.volume.push(item[5])
})

console.log(result)

Answer 3

您可以使用 zip 函数按索引压缩嵌套数组，并将结果传递给预期数据形状的构造函数。

const zip = (...r) => [...r[0]].map((_, c) => r.map(s => s[c]));

const Data = ([_timestamp, open, close, high, low, volume]) => ({ open, close, high, low, volume });

// usage
const data = [[1627875900, 434.75, 435.8, 432.55, 434.9, 1750806], [1627876800, 434.75, 435.2, 432.7, 433, 905388], [1627877700, 432.9, 433.75, 431.8, 433.55, 689338]];

const result = Data(zip(...data));

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 4

这很容易构建在一些可重用的辅助函数之上。 transpose 翻转矩阵，使列变成行。 zipObj 采用键数组和值数组，并生成一个对象，该对象具有与每个键关联的相应值。有了这些，我们几乎可以简单地写出这个：

const transpose = (xs) => 
  xs [0] .map ((_, i) => xs .map (r => r[i]))
  
const zipObj = (keys) => (vals) => 
  Object .fromEntries (transpose ([keys, vals]))

const restructure = (data) => 
  zipObj (['timestamp', 'open', 'high', 'low', 'close', 'volume']) (transpose (data))

const data = [[1627875900, 434.75, 435.8, 432.55, 434.9, 1750806], [1627876800, 434.75, 435.2, 432.7, 433, 905388], [1627877700, 432.9, 433.75, 431.8, 433.55, 689338]];

console .log (restructure (data))

.as-console-wrapper {max-height: 100% !important; top: 0}

这包括 timestamp 个值。如果你不想要它们，那么我们可以用另一个助手删除每个（tail 只是 returns 一个没有第一个值的数组）然后简单地不在键列表中包含 timestamp .您可以通过展开以下代码段来查看：

const tail  = (xs) => xs .slice (1)

const transpose = (xs) => 
  xs [0] .map ((_, i) => xs .map (r => r[i]))
  
const zipObj = (keys) => (vals) => 
  Object .fromEntries (transpose ([keys, vals]))

const restructure = (data) => 
  zipObj (['open', 'high', 'low', 'close', 'volume']) (transpose (data .map (tail)))

const data = [[1627875900, 434.75, 435.8, 432.55, 434.9, 1750806], [1627876800, 434.75, 435.2, 432.7, 433, 905388], [1627877700, 432.9, 433.75, 431.8, 433.55, 689338]];

console .log (restructure (data))

.as-console-wrapper {max-height: 100% !important; top: 0}

如何将未标记的数组排列成标记的数组？

How to arrange an unlabeled array into a labelled array?

javascript

algorithm

algorithmic-trading

node.js

ta-lib