DTO 和实体映射

Question

我正在构建一个 Spring Rest 应用程序，我需要 DTO 方面的帮助并将结果解析到端点

这是json我return此刻到终点：

{
  "id": 1,
  "name": "Ella - IPA Is Dead",
  "description": "2015 IPA is Dead Series. Supremely floral, this hugely under-rated hop is related to Galaxy and was first cultivated in the Australian state of Victoria.",
  "method": {
      "mash_temp": [
       {
           "temp": {
               "value": 65
           }
       }
  ]
 }
}

我不想return这个json的“方法”，我只需要“id”、“name”、“description”、“mash_temp”-所以它应该是这样的：

{
  "id": 1,
  "name": "Ella - IPA Is Dead",
  "description": "2015 IPA is Dead Series. Supremely floral, this hugely under-rated hop is related to Galaxy and was first cultivated in the Australian state of Victoria. Initially given the same name as a certain Eurolager, their lawyers got involved and the St- prefix was dropped. Ella displays subtle notes of spice, but is fundamentally a truly floral bouquet, redolent of the Southern Hemisphere.",
  "mash_temp": [
   {
      "temp": {
         "value": 65
         }
      }
  ]
}

这些是我现在使用的实体：

啤酒实体：

@Entity
public class Beer implements Serializable {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "beer_id", unique = true, nullable = false)
    private Integer id;

    @Column(name = "name", nullable = false)
    private String name;

    @JsonProperty("description")
    @Column(name = "description", nullable = false, columnDefinition = "TEXT")
    private String description;

    @JsonProperty("method")
    @OneToOne(cascade = CascadeType.ALL)
    private Method method;
}

方法实体：

@Entity
public class Method implements Serializable
{

     @JsonIgnore(value = true)
     @Id
     @GeneratedValue(strategy = GenerationType.IDENTITY)
     private Integer id;

     @JsonProperty("mash_temp")
     @OneToMany(cascade = CascadeType.ALL)
     @JoinColumn(name = "mash_temp")
     private List<MashTemp> mash_temp = new ArrayList<>();
}

MashTemp 实体：

@Entity
public class MashTemp implements Serializable
{

    @JsonIgnore(value = true)
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Integer id;

    @OneToOne(cascade = CascadeType.ALL)
    private Temp temp;

    @ManyToOne
    private Method method;
}

临时实体：

@Entity
public class Temp implements Serializable
{

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Integer id;

    private Integer value;

    @JsonIgnore(value = true)
    private String unit;

    @OneToOne
    private MashTemp mashTemp;
}

有谁知道如何从这个实体创建 DTO 但没有“方法”字段？

这也是我的控制器：

@GetMapping("/beers")
public ResponseEntity<Set<Beer>> getAllBeers()
{
    return new ResponseEntity<>(beerService.getAllBeers(), HttpStatus.OK);
}

@GetMapping("/beers/{id}")
public ResponseEntity<Beer> getById(@PathVariable Integer id) {
    Beer beer = beerService.findById(id);

    return new ResponseEntity<>(beer, HttpStatus.OK);
}

Answer 1

查看 @JsonUnwrapped 注释 (https://fasterxml.github.io/jackson-annotations/javadoc/2.8/com/fasterxml/jackson/annotation/JsonUnwrapped.html)。可以放在Beerclass中的method字段，然后Methodclass的属性直接在同级序列化来自 Beer.

的

DTO 和实体映射

DTO and Entities mapping

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dto