在控制台中获取数组值

Question

我有一个数组 (tot)，里面有数组。我需要检查 (tot) 中的每个条目的值，这是通过在控制台键入 AA[3] 完成的，但是，当我从脚本执行它时，AA[3] 不会 return 任意值！

这是我的脚本：

tot=["AA","AB","AC"];
AA=["1","2","3","4","5","6","7"];
AB=["1","2","3","4","5","6","7"];
AC=["1","2","3","4","5","6","7"];

for (let i = 0; i < tot.length; i++)  
{
tot[i]+'[2]';
}

Answer 1

您的代码没有输出任何内容，因为您没有要求它输出任何内容。还有那一行： tot[i] + '[2]' 是不正确的。你到底想在那里做什么。我将其更改为向每个元素添加“[2]”字符串，但似乎这不是您想要的。

tot=["AA","AB","AC"];
AA=["1","2","3","4","5","6","7"];
AB=["1","2","3","4","5","6","7"];
AC=["1","2","3","4","5","6","7"];

for (let i = 0; i < tot.length; i++)  
{
tot[i]+='[2]';
}
console.log(tot)

Answer 2

你可以试试：

const tot = [
    ["1","2","3","4","5","6","7"],
    ["1","2","3","4","5","6","7"],
    ["1","2","3","4","5","6","7"]
];

for (let i = 0; i < tot.length; i++)  
{
    console.log(tot[i][2]);
}

Answer 3

变量不能像函数一样工作。不要在循环中写入变量，请尝试：

console.log(tot);

此外，我假设你打算做 var tot = new Array(AA, AB, AC);

var AA=["1","2","3","4","5","6","7"];
var AB=["1","2","3","4","5","6","7"];
var AC=["1","2","3","4","5","6","7"];
var tot= new Array(AA,AB,AC);

for (let i = 0; i < tot.length; i++)  
{
tot[i].push("2")
console.log(tot[i]);
}

Answer 4

要遍历 tot 数组中的每个数组，您必须嵌套两个 for 循环，并且 console.log 嵌套 for 循环中的每个值：


const AA=["1","2","3","4","5","6","7"];
const AB=["1","2","3","4","5","6","7"];
const AC=["1","2","3","4","5","6","7"];
const tot=[AA,AB,AC];

const logArray = (tot) => {
  for (let i = 0; i < tot.length; i++) {
    console.warn(`tot[${i}] contains:`);
    for (let j = 0; j < tot[i].length; j++) {
      console.log(tot[i][j]);
    }
  }
};

Answer 5

I have an array (tot) with arrays in it

实际上这是不准确的。您有一个数组，其中包含不是数组的字符串值。数组中的字符串值与某些数组的名称相匹配。取而代之的是，您可能想使用数组对象，例如：

let AA=["1","2","3","4","5","6","7"];
let AB=["1","2","3","4","5","6","7"];
let AC=["1","2","3","4","5","6","7"];
let tot={AA,AB,AC};
let index = 5;

for (let key in tot) {
    console.log(`${key}[${index}]: ${tot[key][index]}`);
}

在控制台中获取数组值

getting array value in console

javascript

arrays

console