在 geom_label 中解析：丰富显示对象时出错：解析错误 (text = text[[i]])=

Question

我使用 ggplot 打印 geom_label，代码如下：

ggplot()+
    geom_label(aes( x = 10, y = 0.545, label = " expression 1 =  p-value = 9.19 e-09 ; CI : [0.00, 0.00]"), 
             label.size = NA , hjust =0.08, size = 3.5, family = "Helvetica")

和我正在尝试以斜体.
打印p 所以我试过了

ggplot()+
    geom_label(aes( x = 10, y = 0.545, label = " expression 1 =  p-value = 9.19 e-09 ; CI : [0.00, 0.00]"), 
             label.size = NA , hjust =0.08, size = 3.5, family = "Helvetica")+
    geom_label(aes( x = 10, y = 0.509, label = paste("expression 2 =  italic(p)-value = 9.19 e-09 ; CI : [0.00, 0.00]")), 
             label.size = NA, hjust =0.08, size = 3.5, family = "Helvetica", parse = T)

哪个 return 我是以下错误信息：

ERROR while rich displaying an object: Error in parse(text = text[[i]]): :1:19: unexpected string constant 1: 'expression 1 : ' 'italic(p)'

你知道错误从何而来以及如何解决吗？

PS : 基于此 post Unexpected symbol error in parse(text = str) with hyphen after a digit, 我也试过

ggplot()+
    geom_label(aes( x = 10, y = 0.545, label = " expression 1 =  p-value = 9.19 e-09 ; CI : [0.00, 0.00]"), 
             label.size = NA , hjust =0.08, size = 3.5, family = "Helvetica")+
    geom_label(aes( x = 10, y = 0.509, label = paste("'expression 2 =  italic(p)-value = 9.19 e-09 ; CI : [0.00, 0.00]'")), 
             label.size = NA, hjust =0.08, size = 3.5, family = "Helvetica", parse = T)

哪个有效，但 return 是我这个

Answer 1

学习help("plotmath").

library(ggplot2)
ggplot()+
  geom_label(aes(x = 10, y = 0.545, 
                 label = " expression 1 =  p-value = 9.19 e-09 ; CI : [0.00, 0.00]"), 
             label.size = NA , hjust =0.08, size = 3.5)+
  geom_label(aes(x = 10, y = 0.509, 
                 label = paste("'expression 2 = ' *  italic(p) * '-value = 9.19 e-09 ; CI : [0.00, 0.00]'")), 
             label.size = NA, hjust =0.08, size = 3.5, parse = T)

我已经删除了 family = "Helvetica"，因为它在我的系统上引起了警告。

在 geom_label 中解析：丰富显示对象时出错：解析错误 (text = text[[i]])=

parse in geom_label : ERROR while rich displaying an object: Error in parse(text = text[[i]])=

r

text-parsing

ggplot2