Laravel 按日期分组

Question

我阅读了一些已经发布的问题 here.But 没有找到满足我要求的任何解决方案。请记住此响应显示有关用户访问商店的签到信息。

分组收集

$this->collection->groupBy(function ($date) {
                return Carbon::parse($date->createdAt)->toDateString();
  }

将返回按日期分组的数据..

回应

{
   "data":{
      "2021-08-31":[
         {
            "avatar":"avatars/IIa1gvCvww5K4geXJHUYTTZm2IKFoK113octfPB1.jpg",
            "name":"General Shop 15"
         },
         {
            "avatar":"avatars/IIa1gvCvww5K4geXJHUYTTZm2IKFoK113octfPB1.jpg",
            "name":"General Shop 15"
         }
      ],
      "2021-08-29":[
         {
            "avatar":"avatars/IIa1gvCvww5K4geXJHUYTTZm2IKFoK113octfPB1.jpg",
            "name":"General Shop 15"
         }
      ],
      "2021-08-20":[
         {
            "avatar":"avatars/GSDrGe8RLGXykvvsEVlWtnqRGbAOoJUuSh7WZhFc.jpg",
            "name":"XYZ Store"
         },
         {
            "avatar":"avatars/GSDrGe8RLGXykvvsEVlWtnqRGbAOoJUuSh7WZhFc.jpg",
            "name":"XYZ Store"
         },
         {
            "avatar":"avatars/GSDrGe8RLGXykvvsEVlWtnqRGbAOoJUuSh7WZhFc.jpg",
            "name":"XYZ Store"
         }
      ]
   }
}

但我希望回复看起来像炸了.. 然后分组日期将显示为..

{
   "data":[
      {
         "date":"2021-08-31",
         "data":[
            {
               "avatar":"avatars/IIa1gvCvww5K4geXJHUYTTZm2IKFoK113octfPB1.jpg",
               "name":"General Shop 15"
            },
            {
               "avatar":"avatars/IIa1gvCvww5K4geXJHUYTTZm2IKFoK113octfPB1.jpg",
               "name":"General Shop 15"
            }
         ]
      },
      {
         "date":"2021-08-29",
         "data":[
            {
               "avatar":"avatars/IIa1gvCvww5K4geXJHUYTTZm2IKFoK113octfPB1.jpg",
               "name":"General Shop 15"
            },
            {
               "avatar":"avatars/IIa1gvCvww5K4geXJHUYTTZm2IKFoK113octfPB1.jpg",
               "name":"General Shop 15"
            }
         ]
      }
   ]
}

Answer 1

您已经收到了您需要的数据。只是为了将数据固定在所需的格式循环中你收到的集合和将其设置为您希望的格式。

Answer 2

您无法在检索数据时在 Mysql 级别修改该响应。你可以做的是在你的集合解析它并相应地修改它之后。这样的事情会起作用：

$counter = 0;
foreach($myCollection->data as $key=>$value){
    $formattedResponse['data'][$counter]['date'] = $key;
    $formattedResponse['data'][$counter]['data'] = $value;
    $counter ++;
}

基于您的 json 输入示例的输出是：

{
    "data": [{
        "date": "2021-08-31",
        "data": [{
            "avatar": "avatars\/IIa1gvCvww5K4geXJHUYTTZm2IKFoK113octfPB1.jpg",
            "name": "General Shop 15"
        }, {
            "avatar": "avatars\/IIa1gvCvww5K4geXJHUYTTZm2IKFoK113octfPB1.jpg",
            "name": "General Shop 15"
        }]
    }, {
        "date": "2021-08-29",
        "data": [{
            "avatar": "avatars\/IIa1gvCvww5K4geXJHUYTTZm2IKFoK113octfPB1.jpg",
            "name": "General Shop 15"
        }]
    }, {
        "date": "2021-08-20",
        "data": [{
            "avatar": "avatars\/GSDrGe8RLGXykvvsEVlWtnqRGbAOoJUuSh7WZhFc.jpg",
            "name": "XYZ Store"
        }, {
            "avatar": "avatars\/GSDrGe8RLGXykvvsEVlWtnqRGbAOoJUuSh7WZhFc.jpg",
            "name": "XYZ Store"
        }, {
            "avatar": "avatars\/GSDrGe8RLGXykvvsEVlWtnqRGbAOoJUuSh7WZhFc.jpg",
            "name": "XYZ Store"
        }]
    }]
}

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